The Student Room Group

Resistivity Question

a metal wire of length 1.4m has a uniform cross sectional area= 7.8x10^-7

resistivity of the metal= 1.7x10^-8

a) calculate resistance => i got this part as 0.03 ohms

b) the wire is now stretched to twice its original length by a process that keeps its volume constant. if the resistivity of the wire remains constant show that the resistance increases to 4R.

for PART B i assumed that the resistance would be 0.12 ohms for obvious reasons.

However when i was double checking for the answer RA/L does not equal the resistivity value.

any help would be appreciated
Reply 1
length has doubled, area has halved so newR = 2lrho/0.5A = 4 origR
Reply 2
yep i forgot that resistance is inversely proportional to area thanks
Reply 3
You're welcome :wink:

Latest