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Finding the pH of strong bases

Question is

Calculate the pH of 0.1 mol dm-3 Ba(OH)2(aq)

Kw = 1.x10-14

do you need more information?

i got pH=13, but i dont think its right, i think i've made a stupid mistake somewhere. any help would be great!
Use pOH = - log [OH-] and pH + pOH = 14 :smile:
Reply 2
Avatar for hodgey90
hodgey90
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EierVonSatan
Use pOH = - log [OH-] and pH + pOH = 14 :smile:


thats a new method! can you elaborate if thats alright?
hodgey90
thats a new method! can you elaborate if thats alright?


Well pH + pOH = 14 just comes from taking logs of Kw = [H+][OH-] = 10-14 you can calculate pOH just in the same way as pH
Reply 4
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hodgey90
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EierVonSatan
Well pH + pOH = 14 just comes from taking logs of Kw = [H+][OH-] = 10-14 you can calculate pOH just in the same way as pH


oh, i think i get it. since you know pH + pOH must equal 14, you can find one to find the other
Reply 5
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hodgey90
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so the answer is 13?
Reply 6
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CatexW
13
I got 13, but I haven't done chemistry for a while...
pOH = -log [2x0.1] = 0.69897... => pH = 14 - 0.69897... = 13.301...
Reply 8
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hodgey90
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8
EierVonSatan
pOH = -log [2x0.1] = 0.69897... => pH = 14 - 0.69897... = 13.301...


oh i see, because there's two OH- ions produced, you have to times the concentration by 2.
thank you, knew i was doing something wrong

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