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what is the rate equation?
3A + B --> C
trial...[A](mol/L)...(mol/L)...Init... rate (mol/L.s)
1.......0.1...........0.1........0.125
2.......0.1...........0.2........0.125
3.......0.2...........0.1........0.250
What is the rate equation?
1) Rate = k[A]
2) Rate = k[A]2
3) Rate= k2
4) Rate = k[A]2
5) Rate = k[A]22
6) Rate = k
7) Rate = k[A]3
8) Rate = k[A]
9) Rate = k[A]2
any ideas?
trial...[A](mol/L)...(mol/L)...Init... rate (mol/L.s)
1.......0.1...........0.1........0.125
2.......0.1...........0.2........0.125
3.......0.2...........0.1........0.250
What is the rate equation?
1) Rate = k[A]
2) Rate = k[A]2
3) Rate= k2
4) Rate = k[A]2
5) Rate = k[A]22
6) Rate = k
7) Rate = k[A]3
8) Rate = k[A]
9) Rate = k[A]2
any ideas?
...
... consider when the conc of B is mulitplied by 2 with no change to the rate - we can draw conclusion that B has to be raised to the zeroth power. What is the last rate divided by the first rate? Note how the conc of A is doubled - can you form some relation to the exponent? e.g. If initially the rate between x + y ---> z was 2 mol dm^3 s^-1 , with the conc of y halved, given x has no effect on the rate, and the rate halves, what is the equation; rate = k [x] ...
... consider when the conc of B is mulitplied by 2 with no change to the rate - we can draw conclusion that B has to be raised to the zeroth power. What is the last rate divided by the first rate? Note how the conc of A is doubled - can you form some relation to the exponent? e.g. If initially the rate between x + y ---> z was 2 mol dm^3 s^-1 , with the conc of y halved, given x has no effect on the rate, and the rate halves, what is the equation; rate = k [x] ...
DeanK22
...
... consider when the conc of B is mulitplied by 2 with no change to the rate - we can draw conclusion that B has to be raised to the zeroth power. What is the last rate divided by the first rate? Note how the conc of A is doubled - can you form some relation to the exponent? e.g. If initially the rate between x + y ---> z was 2 mol dm^3 s^-1 , with the conc of y halved, given x has no effect on the rate, and the rate halves, what is the equation; rate = k [x] ...
... consider when the conc of B is mulitplied by 2 with no change to the rate - we can draw conclusion that B has to be raised to the zeroth power. What is the last rate divided by the first rate? Note how the conc of A is doubled - can you form some relation to the exponent? e.g. If initially the rate between x + y ---> z was 2 mol dm^3 s^-1 , with the conc of y halved, given x has no effect on the rate, and the rate halves, what is the equation; rate = k [x] ...
no need to shout...
charco
no need to shout...
... it was supposed to be red but i must have changed the wrong thing...
Given that when the concentration of B is doubled, the rate does not change, we can say the reaction is zero order with respect to B. When the concentration of A is doubled however, the rate also doubles, therefore making the order of reaction with respect to A first order. A zero-order reactant is exempt from the rate equation, so the answer would be 1, rate=k[A].
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