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AQA A2 Synoptic question
http://www.users.totalise.co.uk/~physics/files/a_level_past_papers/Jun03/AQA-PA10-W-QP-Jun03.pdf
question 5d.
im unsure on how to work out the constants from the equation
v = kr^n
my idea was to take logs off both sides
logv = nlogKr
nut not sure from this how to work out n and k, thanks if you can help
question 5d.
im unsure on how to work out the constants from the equation
v = kr^n
my idea was to take logs off both sides
logv = nlogKr
nut not sure from this how to work out n and k, thanks if you can help
Taking logs of both sides:
logv = logk + nlogr
To understand why the equation looks like this, use log laws and work backwards, i.e.:
logv = logk + logrn {Raise r to the power of n, as by log laws alogb <=> logba}
logv = log(krn) {By log laws, loga + logb = log(ab), so long the bases are the same)
Back to the original equation: notice how it's similar to the form y = mx + c. From here you can work out the constants
logv = logk + nlogr
To understand why the equation looks like this, use log laws and work backwards, i.e.:
logv = logk + logrn {Raise r to the power of n, as by log laws alogb <=> logba}
logv = log(krn) {By log laws, loga + logb = log(ab), so long the bases are the same)
Back to the original equation: notice how it's similar to the form y = mx + c. From here you can work out the constants
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