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I hate these type of Q's....

how would you go about doing the following:

Two quantities, x and θ, vary with time and are related by the equation
x = 5sinθ - 4cosθ

i) find the value of x when θ = pi/2 (thats easy, just subst in the above)

ii) when θ = pi/2, its rate of increase (in suitable units) is given by dθ/dt = 0.1
show that at that moment dx/dt = 0.4

how would you go about doing the second part of the question.

thanks for your help guys, much appreciated.
Reply 1
x = 5sinθ - 4cosθ
dx/dt = 5cos@ d@/dt + 4sin@ d@/dt
dx/dt = 5 cos (pi/2) . 0.1 + 4 sin(pi/2) 0.1 = 0.4 Q.E.D.
Reply 2
yazan_l
x = 5sinθ - 4cosθ
dx/dt = 5cos@ d@/dt + 4sin@ d@/dt
dx/dt = 5 cos (pi/2) . 0.1 + 4 sin(pi/2) 0.1 = 0.4 Q.E.D.


thanks :smile:
Reply 3
glad to help

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