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Old 11-04-2009: 11th April 2009 15:03 #1 
yhsa yhsa is offline
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Default The Material/Lagrangian Derivative
 
Hello,

I'm having difficulty with some fluid dynamics, specifically the material derivative, i.e.  \frac{DX}{Dt} where X can be a number of variables.

If I go through the theory and point out where I'm getting confused, perhaps a maths genius can help me out?

Ok...

Consider a parcel, of say air, moving along a vector field. Rather than considering the rate of change of air at each point in a fixed coordinate system, we follow the parcel and describe the rates of change of various variables of that parcel as it moves along.

Let the parcel of air have temperature T at a position x(t), y(t), z(t) such that T = T(x, y, z, t).

So,

dT = \frac{\partial T}{\partial x}dx + \frac{\partial T}{\partial y}dy + \frac{\partial T}{\partial z} dz + \frac{\partial T}{\partial t}dt

<--- Confused from here--->
Right. My notes then say "the material derivative is \displaystyle\lim_{\partial t \to 0} (\frac{\partial T}{\partial t})
Ok...I don't really understand what happens there, and the next step is...

\frac{DT}{Dt} = \frac{\partial T}{\partial x} \frac{Dx}{Dt} + \frac{\partial T}{\partial y} \frac{Dy}{Dt} + \frac{\partial T}{\partial z} \frac{Dz}{Dt} + \frac{\partial T}{\partial t}

<---until here--->

So what's happening there? The next step makes sense...

\frac{DT}{Dt} = u \frac{\partial T}{\partial x} + v \frac{\partial T}{\partial y} + w \frac{\partial T}{\partial z} + \frac{\partial T}{\partial t}

 = \frac{\partial T}{\partial t} + \textbf{u}.\nabla T

So it's the bit in the middle, with the limit, that really confuses me at the moment.

Any help would be greatly appreciated!

ashy (from his revision account while his main account is blocked by request )

Last edited by yhsa : 11-04-2009 at 15:06.

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Old 11-04-2009: 11th April 2009 15:42 #2 
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Default Re: The Material/Lagrangian Derivative
 
Originally Posted by yhsa
<--- Confused from here--->
Right. My notes then say "the material derivative is \displaystyle\lim_{\partial t \to 0} (\frac{\partial T}{\partial t})
Does this say  \frac{\delta T}{\delta t} or \frac{\partial T}{\partial t} in your notes?
 

Last edited by yusufu : 11-04-2009 at 17:31.

Old 11-04-2009: 11th April 2009 16:16 #3 
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Default Re: The Material/Lagrangian Derivative
 
Originally Posted by yusufu
Does this say \frac{\delta T}{\delta x} or \frac{\partial T}{\partial x} in your notes?

\frac{\delta t}{\delta x}, you're right, sorry. Similarly it's \displaystyle\lim_{\delta t \to 0}

It should also be:

dT = \frac{\partial T}{\partial x}\delta x + \frac{\partial T}{\partial y}\delta y + \frac{\partial T}{\partial z} \delta z + \frac{\partial T}{\partial t}\delta t

I don't really understand the difference, though

Last edited by yhsa : 11-04-2009 at 16:21.

Old 11-04-2009: 11th April 2009 17:31 #4 
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Default Re: The Material/Lagrangian Derivative
 
Originally Posted by yhsa
\frac{\delta t}{\delta x}, you're right, sorry. Similarly it's \displaystyle\lim_{\delta t \to 0}

It should also be:

dT = \frac{\partial T}{\partial x}\delta x + \frac{\partial T}{\partial y}\delta y + \frac{\partial T}{\partial z} \delta z + \frac{\partial T}{\partial t}\delta t

I don't really understand the difference, though
\frac{dT}{dt} is the limit of \frac{\delta T}{\delta t} as {\delta t} \to 0.

Just means you're actually taking the derivative.
 
Old 11-04-2009: 11th April 2009 18:35 #5 
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Default Re: The Material/Lagrangian Derivative
 
Originally Posted by yusufu
\frac{dT}{dt} is the limit of \frac{\delta T}{\delta t} as {\delta t} \to 0.

Just means you're actually taking the derivative.
I am made of fail.

Thanks. Send a PM to "ashy" and I'll rep you when I can access the account again (June 4th)
Old 11-04-2009: 11th April 2009 18:41 #6 
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Default Re: The Material/Lagrangian Derivative
 
Originally Posted by yhsa
I am made of fail.

Thanks. Send a PM to "ashy" and I'll rep you when I can access the account again (June 4th)
lol. OK.
 
Old 11-04-2009: 11th April 2009 18:43 #7 
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Default Re: The Material/Lagrangian Derivative
 
Originally Posted by yhsa
I am made of fail.

Thanks. Send a PM to "ashy" and I'll rep you when I can access the account again (June 4th)

ashy has chosen not to receive private messages or may not be allowed to receive private messages. Therefore you may not send your message to him/her.

Never mind.
 
Old 11-04-2009: 11th April 2009 18:43 #8 
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Default Re: The Material/Lagrangian Derivative
 
Originally Posted by yusufu
lol. OK.
When I do check it I'll be like "oo a PM" then laugh at myself for forgetting, despite writing this now.

What?

I don't get why the lecturer has to use capital D, now that I look at it. Seems a little...misleading. Never mind.
Old 11-04-2009: 11th April 2009 18:45 #9 
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Default Re: The Material/Lagrangian Derivative
 
Originally Posted by yusufu
ashy has chosen not to receive private messages or may not be allowed to receive private messages. Therefore you may not send your message to him/her.

Never mind.
Bah. Hmm. Should be a separate "ban by request" PM feature, really.

I shall find a way to remember do give you many hundreds of points
Old 11-04-2009: 11th April 2009 19:20 #10 
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Default Re: The Material/Lagrangian Derivative
 
Originally Posted by yhsa
Bah. Hmm. Should be a separate "ban by request" PM feature, really.

I shall find a way to remember do give you many hundreds of points
I've put this thread into my favourites and labelled it "Not to be opened until June 4th 2009".
 
Old 11-04-2009: 11th April 2009 19:37 #11 
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Default Re: The Material/Lagrangian Derivative
 
Originally Posted by yusufu
I've put this thread into my favourites and labelled it "Not to be opened until June 4th 2009".
 
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