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Spring constant

speed c of a pulse along a suspened mental slinky is given by

c= square root[k(l^2)/m]

where m and l are the total mass and the suspended length of the slinky respectively and k is the constant in F=kx i.e the spring constant.

The slinky is cut in half and one half is now suspended in a similar manner. the speed of the pulse on a half slinky with mass m/2 and length l/2 is found to be the same as that on a whole slinky. What does this tell you about the value of k for the half slinky?


Aparently k is double that of a spring, but i have no idea why.

Thanks
Reply 1
Avatar for suneilr
suneilr
3
Unparseable latex formula:

c_1=\sqrt{\frac{k_1l^2}{m}} = c_2 = \sqrt{\frac{k_2(\frac{l}{2})^2}{\frac{m}{2}}



From this you get k2=2k1 k_2 = 2k_1

Hope this makes sense.
Reply 2
Avatar for sonic23
sonic23
OP
11
suneilr
Unparseable latex formula:

c_1=\sqrt{\frac{k_1l^2}{m}} = c_2 = \sqrt{\frac{k_2(\frac{l}{2})^2}{\frac{m}{2}}



From this you get k2=2k1 k_2 = 2k_1

Hope this makes sense.


Thanks i actually has the same approach just wasnt sure it was valid:rolleyes:

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