Past paper question help (AS OCR)

Could someone please check if my answers to this question are right?
My working is done in blue, drawing in black and red question mark is where i need help. Please ignore the undone bits

(see attachment)

+rep for those who can help me out

Sorry for the large height of the image, you may have to zoom in

I think 'C' and 'D' in e(ii) are: cyclohex-1,3-diene, and cyclo-hex-1,4-diene.

Though I could be wrong, we don't do much cyclic chemistry on AQA.


For the polymer question, I'd just draw the cyclohexane ring, but with two bonds coming from carbons 1 and 2 that aren't bonded to anything.

I.e. Poly(ethene)


But again, we don't do much cyclic chemistry with AQA, so I could be wrong. I'm interested to see what the cavalry say

Thanks for your help,
I also thought thats the answer for C and D but arent they the same, 3/4 depends on which way you go around the circle :P:

I know polymerization of linear compounds but am struggling with cyclic compounds in general.

No. They're not the same.
Cyclohex-1,3-diene:

Cyclohex-1,4-diene:




Just draw it the same way you would with a linear compound and see what the mark scheme says after

Here's a badly drawn example of how I'd do it:

Thanks for your help,
I also thought thats the answer for C and D but arent they the same, 3/4 depends on which way you go around the circle :P:
I know polymerization of linear compounds but am struggling with cyclic compounds in general.
What a bad past paper, i was getting high 80s/90s and this one (along with other evil bits) comes along and gives me a mid 70

The suggestions given by Knickerz are correct.

The 1,3 and the 1,4 isomer are not the same. One has the double bonds conjugated and the other has them opposite each other.

The polymer is exactly the same (in principle) as any other addition polymer.

i am still not sure about the polymerization bit, you reckon its polycyclohexane?

Poly(cyclohexene) I would think...

I really have no idea whether both or only one double bond will break
Searching google suggests polyhexene doesnt exist

I think the question just asks about cyclohexene, which implies that there's just the one double bond.

Don't know then. It's probably poly(cyclohexane), but I presumed it would be poly(cyclohexene) because poly(ethene) doesn't have any double bonds if you look at my previous post, but because it's C₂H₄. I thought the same principle would apply here.

Probably the same as when I wrote 1,3-hexacyclodiene instead of 1,3-cyclohexadiene !...

.... about a bottle of red wine and a couple of Marstons.