Hellllppp!!!!chemistry Hellp!@@!!

(c) Sulphur dioxide is easily oxidised in the presence of water.
SO2 + 2H2O – 2e– → SO4(2–) + 4H(+)

(ii) To aqueous sulphur dioxide, acidified barium chloride solution is added. The mixture
remains clear. When bromine is added, a thick white precipitate forms. What is the
white precipitate? Explain why it forms.
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HELPPP!!!!!!! CAN ANYONE ANSWER THIS?

Reply 1

fishpie57

Hmmm.... I do A-level chem and I'm now puzzled! I thought barium chloride was the test for sulphate ions, so if you add barium chloride to a solution with sulphate ions, you should get a white precipitate of barium sulphate... Hmmm!

What board are you doing for Chemistry?! I really am baffled and ashamed at myself for not being able to help...

I'm as keen as you to find the answer to this now!

Reply 2

Holden

ppt is barium chloride. Br2 is reduced to 2Br- (0 to -1) and SO2 is oxidised to SO4(2-) (+4 to +6).
Overall reaction is:
SO2 + 2H2O + Br2 → H2SO4 + 2HBr
The H2SO4 then reacts with BaCL2 giving BaSO4 (ppt) and HCl