The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

This discussion is now closed.

Check out other Related discussions

general power function

i know that

y=a^x becoes a^x ln(x)

what does y=a^-x become?

im just being a bit slow on this.. so help would be nice
Reply 1
Avatar for Zhen Lin
Zhen Lin
12
If you are referring to differentiation, then dydx=axln⁡a\displaystyle \frac{dy}{dx} = a^x \ln a. For y=a−xy = a^{-x}, use the chain rule.
Reply 2
Avatar for vc94
vc94
12
Do you mean derivative? Then a^x becomes ln(a)a^x.

Write a^-x = (1/a)^x ...see what to do?
Reply 3
Avatar for MPen
MPen
OP
vc94
Do you mean derivative? Then a^x becomes ln(a)a^x.

Write a^-x = (1/a)^x ...see what to do?



ah right.. i see what you mean, thanks guy
Reply 4
Avatar for MPen
MPen
OP
just so i know.. how does that work out..

i dont wanna be too sure of myself and then screw up getting my A
Reply 5
Avatar for MPen
MPen
OP
right the question i have is y = 2^x + 2^(-x), find the equation to the tangent at the point (2, 4.25)

would dy/dx give:

dy/dx = 2^(x) ln2 - 2^(-x) ln2 ??
Reply 6
Avatar for MPen
MPen
OP
MPen
right the question i have is y = 2^x + 2^(-x), find the equation to the tangent at the point (2, 4.25)

would dy/dx give:

dy/dx = 2^(x) ln2 - 2^(-x) ln2 ??


never mind.. got it (Y) thanks for the help though

Related discussions

Latest

Trending

Trending

Articles for you