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What's the integral of sin(x)sinh(x)?

Ben.S.

I don't have the answer to this particular, indefinite integral, and I need to know if I've got it right. Also, I can't find it anywhere on the internet!

The answer I get is:

1/2 [sin(x)cosh(x) - cos(x)sinh(x)] + C

Thanks,

Ben

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Reply 1

Reply 2

Adhsur

Lord Huntroyde

LOL!!!

Reply 3

Juwel

Huntroyde, you get your sig quotes from Private Eye don't you!

Reply 4

ZJuwelH

Huntroyde, you get your sig quotes from Private Eye don't you!

Ondeed I do, but my purchasing of P.E. Mediaballs today will mean I can change quotes more than just fortnightly.

Reply 5

Juwel

I would know this if I knew the integral of sinhx, or what sinhx was for that matter. But I think the integral of sinx is -cosx...

Reply 6

Linda

Could it be -1/h cos (hx) + C?

Reply 7

Linda

Nevermind, mis read your question. What do you mean exactly? sin^2(x)or what?

Reply 8

Ben.S.

Linda

Nevermind, mis read your question. What do you mean exactly? sin^2(x)or what?

You actually have helped a bit. I accidentally omitted the constant of integration - thanks.

Ben

Reply 9

Ben.S.

Sinh(x) is a hyperbolic function and, unfortunately, is not sin(hx).

Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]

Ben

Reply 10

king of swords

Ben.S.

Sinh(x) is a hyperbolic function and, unfortunately, is not sin(hx).

Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]

Ben

please tell me that's P6 :confused:

(I'm only doing up to P5 this year)

Reply 11

Ben.S.

king of swords

please tell me that's P6 :confused:

(I'm only doing up to P5 this year)

It's complex numbers.
Oh, and it's absolute rubbish what I've written - I only bloody DIFFERENTIATED THE FLIPPING THING!!!!!

Ben

Reply 12

Juwel

king of swords

please tell me that's P6 :confused:

(I'm only doing up to P5 this year)

Better not be P6, I'm doing that!

I saw all that and thought: in the words of Snoop Dogg, "wha-wha-wha-whaaaaaaa???"

Reply 13

Linda

Ben.S.

It's complex numbers.
Oh, and it's absolute rubbish what I've written - I only bloody DIFFERENTIATED THE FLIPPING THING!!!!!

Ben

If you differentiated it, it wouldn't be +c, now would it?

Reply 14

king of swords

Linda

If you differentiated it, it wouldn't be +c, now would it?

ok so he did a hybrid of integration and differentiation lol

Reply 15

Juwel

king of swords

ok so he did a hybrid of integration and differentiation lol

Intentiation or differegration... Newton and Fermat would be turning in their graves...

Reply 16

kikzen

i think hyperbolic functions are p5.

im only going up to p4, thank god :]

Reply 17

icy

Ben.S.

Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]

Ben

huh?
what is h?

Reply 18

mikesgt2

The answer is:

(sinxcoshx-cosxsinhx)/2

Reply 19

Ben.S.

icy

huh?
what is h?

Right, so I've got my new, improved (non-dintegrated) answer now!

I didn't do further - do you do hyperbolics like that?
The 'h' just means that we aren't dealing with sines and cosines any more.

Ben