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29-05-2005: 29th May 2005 18:54
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#3
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Vengeful, Imperial Overlord of The Student Room
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Join Date: Aug 2004
Location: Leamington Spa
Posts: 4,917
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Originally Posted by oceane
Hello
Edexcel exercise 6e pg 110 question 7:
x (d2y/dx2) - 2 (dy/dx) + x=0 Using the substitution dy/dx=v
Not sure how to go about this one, have played around with it but don't really know what I'm looking for so if you can see it please tell me!
Cheers
dy/dx=v, d^2y/dx^2=dv/dx
xdv/dx-2v+x=0
dv/dx+v[-2/x]+1=0
dv/dx+v[-2/x]=-1
Integrating factor: e^INT(-2/x) dx = e^(-2lnx)=e^(lnx^-2)=x^-2=1/(x^2)
v/x^2=INT -1/x^2 dx
v/x^2=INT-x^-2 dx
v/x^2=x^-1+C
v=x+Cx^2
dy/dx=x+Cx^2
y=0.5x^2+Ax^3+B
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