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Old 29-05-2005: 29th May 2005 18:38 #1 
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Default P4 2nd order diff. eqtns
 
Hello

Edexcel exercise 6e pg 110 question 7:

x (d2y/dx2) - 2 (dy/dx) + x=0 Using the substitution dy/dx=v

Not sure how to go about this one, have played around with it but don't really know what I'm looking for so if you can see it please tell me!

Cheers
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Old 29-05-2005: 29th May 2005 18:49 #2 
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use the substitution to get a 1st order d.e.
 
Old 29-05-2005: 29th May 2005 18:54 #3 
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Originally Posted by oceane
Hello

Edexcel exercise 6e pg 110 question 7:

x (d2y/dx2) - 2 (dy/dx) + x=0 Using the substitution dy/dx=v

Not sure how to go about this one, have played around with it but don't really know what I'm looking for so if you can see it please tell me!

Cheers
dy/dx=v, d^2y/dx^2=dv/dx
xdv/dx-2v+x=0
dv/dx+v[-2/x]+1=0
dv/dx+v[-2/x]=-1
Integrating factor: e^INT(-2/x) dx = e^(-2lnx)=e^(lnx^-2)=x^-2=1/(x^2)
v/x^2=INT -1/x^2 dx
v/x^2=INT-x^-2 dx
v/x^2=x^-1+C
v=x+Cx^2
dy/dx=x+Cx^2
y=0.5x^2+Ax^3+B
Old 29-05-2005: 29th May 2005 19:08 #4 
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Neat. Thanks to you both.
 
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