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Revision:Chains and Rings - Organic Chemistry

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TSR Wiki > Study Help > Subjects and Revision > Revision Notes > Chemistry > Chains and Rings - Organic Chemistry


Contents

Aldehydes and Ketones

Reduction

Reagents: NaBH4

Reaction: Nucleophilic Addition


Aldehyes are reduced to primary alcohols

\displaystyle \mathsf{CH_3CH_2CHO + 2[H]} \longrightarrow \mathsf{CH_3CH_2CH_2OH}


Ketones are reduced to secondary alcohols

\displaystyle \mathsf{CH_3COCH_3 + 2[H]} \longrightarrow \mathsf{CH_3CH(OH)CH_3}


Aldehyde or Ketone???

  • Reaction with 2,4-dinitrophenylhydrazine
  • Add this to mixture, get bright orange precipitate if aldehyde or ketone present.

THEN,

  • Using the product from this reaction
    • recystallise
    • Measure Melting Point
    • Use data book to find out structure


Test for aldehydes

Oxidation tests because only aldehydes undergo oxidation! RCH0 + [0] gives RCOOH.

1st method

  • refluxing with acidified dichromate(VI)(aq) ions
  • Results: Orange to green shows aldehyde has been oxidised to carboxylic acid.

2nd method

  • use tollens reagent (made by ammonia & silver nitrate) warm this mixture.
  • Results: Silver mirror forms if aldehyde has been oxidised to a carboxylic acid.
  • Aldehyde gets oxidised to carboxylic acid, while Ag+ ions are reduced to silver metal.


Another reaction we must know:

Formation of 2-hydroxypropanoic acid using ethanal

  • Stage 1
    • Reagents: HCN
    • Conditions KCN
    • Reaction Nucleophilic Addition
    • Equation: \displaystyle \mathsf{CH_3CHO + HCN} \longrightarrow \mathsf{CH_3CH(OH)CN}
  • Stage 2
    • Reagents: H+ (aq)
    • Conditions : Warm, Reflux
    • Reaction Hydrolysis
    • Equation: \displaystyle \mathsf{CH_3CH(OH)CN + 2H_20 + H^+} \longrightarrow \mathsf{CH_3CH(OH)COOH + NH_4}


NMR Checklist

  • Count the number of peaks
  • Explain the positions of the peak:
  • Say what type of proton (e.g. the protons in the CH3 group)
  • Say where the chemical shift is
  • Say ‘this is consistent with the data sheet value’
  • How many protons are in that environment
  • Spitting (use n + 1 ) rule, where n is the number of hydrogen’s on the adjacent carbon


Use of D2O in N.M.R.

  • Protons in -OH are labile.
  • If an organic molecule contains –OH groups & is mixed with deuterium oxide then the protons are replaced with deuterium atoms . Since the deuterium atom has an even number of particles in its nucleus (a proton and a neutron) it does not show up in proton N.M.R.
  • So, if spectra are taken of a molecule before and after the use of D2O, a comparison of the two spectra can reveal any labile hydrogens in the molecule.


Arenes

Structure of Bezene

  • Planar Molecule
  • All C-C bonds same length
  • P orbitals above and below the ring
  • Overlapping of p-orbitals forms pi bonds
  • Electrons are delocalised


Resistance to electrophilic addition

  • Doesn't polarise electrophiles well
  • Electrophiles less attracted
  • Stable delocalised system would need to be disrupted


Electrophilic Substitution

  • Nitration of bezene
  • Reagents: \displaystyle \mathsf{HNO_3 and H_2SO_4} (catalyst)
  • Conditions: approx. 60°C
  • Equation: \displaystyle \mathsf{C_6H_6 + HNO_3} \longrightarrow \mathsf{C_6H_5NO_2 + H_20}
  • Mechanism:
    • Step 1 = generation of electrophile: \displaystyle \mathsf{2H_2SO_4 + HNO_3 2HSO_4^- + NO_2+ + H_3O^+}
    • Step 2 = Electrophilic Substitution
    • Step 3 = regeneration of catalyst: \displaystyle \mathsf{H^+ + HS0_4^-}\longrightarrow \mathsf{H_2SO_4}


  • Halogenation (can do this with Br2 as well)
  • Reagents : Cl2 and ALCl3 (catalyst)
  • Conditions: anhydrous
  • Equation: \displaystyle \mathsf{C_6H_6 + Cl_2} \longrightarrow \mathsf{C_6H_5Cl + HCl}
  • Mechanism:
    • Step 1 = generation of electrophile: \displaystyle \mathsf{Cl_2 + AlCl_3}\longrightarrow \mathsf{ Cl^+ + AlCl_4}
    • Step 2 = Electrophilic Substitution
    • Step 3 = regeneration of electrophile: \displaystyle \mathsf{H^+ + AlCl_4} \longrightarrow \mathsf{AlCl_3 + HCl}


Phenols

Form salts by its reactions with NaOH and Na

\displaystyle \mathsf{C_6H_5OH + NaOH} \longrightarrow \mathsf{C_6H_5O-Na^+ + H_20}

\displaystyle \mathsf{C_6H_5OH + Na} \longrightarrow \mathsf{C_6H_5O-Na^+ + \frac{1}{2} H_2}

Phenols react with bromine. the bromine is decolorised and white cystals of 2,4,6-tribromophenol are formed.


Phenol Vs Bezene

  • Phenol does not require halogen carrier & reacts instantly with bromine
  • OH- group activates benzene ring
  • This increases electron density around ring (especially at 2,4, 6)
  • This polarises the halogen & increases the attraction for the halogen


Uses of phenols

TCP is used as antiseptics & disinfectants!


Polymers

Addition Polymerisation

  • Sigma bond breaks
  • Many molecules join on


Addition Polymers can have different structures because:

  • For any polymer other than poly(ethene), the carbon atom attached to the R group in the alkene unit becomes a chiral centre when a polymer chain is formed: (with 4 different groups attached)


Side groups can be arranged in either:

  • Alternating chirality = Syndiotactic
  • Random chirality = Atactic
  • Same chirality = Isotactic


Properties

Isotactic = chains closely packed = Strong intermolecular forces = High Melting Point

Syndiotactic = chains closely packed = Strong intermolecular forces = High Melting point

Atactic = lack of regularity makes it impossible for the chains to lie closely together = Weaker intermolecular forces = Low Melting point


Condensation Polymerisation

  • A molecule of water is eliminated
  • Ester or peptide link will be formed
  • Polyamides = di-carboxylic acid + diamine = amide link
  • Polyesters = di-carboxylic acid + diol = ester link
  • Polypeptides/Proteins = many amino acids joined = amide link


Polymers we MUST know (for OCR)

  1. Terylene - Monomers = benzene-1,4-dicarboxylic acid and ethane-1,2-diol
    • Uses = fibres, clothing
  2. Kelvar - Monomers = benzene-1,4-dicarboxylic acid and benzene-1,4-diamine
    • Uses = bullet proof clothing, tennis rackets
  3. Nylon-6,6 - Monomers = hexane-1,6-dicarboxlic acid and 1,6-diaminohexane
    • Uses = fibres, clothing


Dipeptides

  • Two amino acids join together.
  • Via condensation reaction
  • COOH reacts with NH2 group.
  • Amide/Peptide link formed.
  • Can be two different structures because you can switch the two R groups around in position.


Polypeptides

Many amino acid monomers join in condensation reaction, forming amide links


Primary Amines

General formula = RNH2


Reactions

With water:

\displaystyle \mathsf{CH_3CH_2NH_2 + H_20} \longrightarrow \mathsf{CH_3CH_2NH_3^+ + OH^-}


With acids:

\displaystyle \mathsf{NH_3 + HCl} \longrightarrow \mathsf{NH_4Cl^-}

\displaystyle \mathsf{CH_3CH_2NH_2 + HCl} \longrightarrow \mathsf{CH_3CH_2NH_3 + Cl^-}


How primary amines act as bases

  • Accepts a proton
  • To give NH3+
  • Using LP of electrons on N of amine group
  • Dative covalent bond formed between N and H


Basicity

  • Depends on the electron density of the lone pair of electrons on the nitrogen atom.
  • Greater e- density = greater base strength


Alkyl groups

  • Have positive inductive effect
  • Push e- away towards the nitrogen atom
  • Increase electron density on the nitrogen atom


Aromatic Amines

  • Have negative inductive effect
  • Pull electrons away the nitrogen atom
  • A benzene ring would allow the lone pair of e- to be delocalised into the ring
  • Decreases the electron density on the nitrogen atom
  • Less likely to capture a proton


Basicity Order

  • Aromatic groups = weakest
  • Ammonia = middle
  • Alkyl groups = strongest




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