Revision:M1 Maths - The Student Room
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Revision:M1 Maths

TSR Wiki > Study Help > Subjects and Revision > Revision Notes > Mathematics > M1 Maths


Here are some basic notes on the content needed for M1 A Level maths exams.


Contents

SUVAT

SUVAT equations are only used when acceleration is constant

  • \displaystyle v = u + at
  • \displaystyle s = \frac{u + v}{2} \times t
  • \displaystyle s = ut + \frac{1}{2}at^2
  • \displaystyle s = vt - \frac{1}{2}at^2
  • \displaystyle v^2 = u^2 + 2as


s = height, distance, displacement
u = initial velocity
v = final velocity
a = acceleration
t = time


\displaystyle \mathsf{acceleration} = \frac{\mathsf{change\ in\ velocity}}{\mathsf{time}}


Acceleration (ms-2) Velocity (ms-1)


  • displacement = how far out of place something is from any position (vector quantity)
  • position = displacement from a fixed origin
  • velocity = rate of change of position (vector quantity; its magnitude is speed)
  • acceleration = rate of change of velocity (vector quantity; as in above equation)
  • distance = how much ground an object has covered during its motion (scalar quantity)
  • speed = magnitude of velocity (scalar quantity)

Types of forces

  • weight (w)
  • friction (f)
  • push and pull (p)
  • normal reaction (r)
  • tension (t) such as in a string, springs, rods
  • thrust (s) such thrust in a spring or rod, but in opposite direction


Force = mass x acceleration

Weight = mass x gravitational pull


Tension is the same on both sides of a pulley

Rope in tension, not thrust


Newton's First Law - A resultant force is required to produce an acceleration

\displaystyle R - mg = ma


Calculating tension

\displaystyle T - mg = ma


A few equations of motion of a car

  • \displaystyle D - T = ma
  • \displaystyle T - mg = ma
  • \displaystyle R - mg = ma
D = driving force,
T = tension,
R = normal reaction or resistance


If a body is moving at a constant speed, the forces are in equilibrium


If a question includes air resistance, the equation for motion is

\displaystyle mg - R = ma


If the air resistance is proportional to the area perpendicular to motion, air resistance is kA

\displaystyle mg - kA = ma


When combining forces, you are finding the resultant force

  • A rough surface causes friction
  • Smooth surface causes no friction


Forces on a car for example will be reduced by

  • driving force (forwards)
  • braking force (backwards)
  • resistance (to motion) air or water act in opposite direction to velocity


Graphs

  • Position - Time
    • Gradient = Velocity
    • Area = Nothing
  • Velocity - Time
    • Gradient = Acceleration
    • Area = Displacement
  • Distance - Time
    • Gradient = Speed
    • Area = Nothing
  • Speed - Time
    • Gradient = Magnitude of acceleration
    • Area = Distance


(DISTANCE is NOT negative, ONLY POSITIVE)


Velocity at an instant can be found by drawing a tangent at the curve of the point


If you have a position, differentiate once for the velocity and differentiate twice for acceleration


Comments

Originally written by ixnayonthehombre on TSR Forums.

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