Revision:OCR Core 3 - Differentiating exponentials and logarithms - The Student Room
The Student Room

Revision:OCR Core 3 - Differentiating exponentials and logarithms

Contents

5. Differentiating exponentials and logarithms

Differentiating exponential functions

An exponential function is simply a function with an exponent in it; in other terms, a function of the form:  f(x) = a^{x} .

Numerical estimates can be used to approximate the gradient at a point, and this can be generalised:

 f^{'} (x) = \lim _{ \delta x \to 0 } \frac{f(x + \delta x) - f(x)}{ \delta x }

Substituting the function in:

 f^{'}(x) = \lim _{ \delta x \to 0 } \frac{ a^{x + \delta x} - a^{x}}{ \delta x } = a^{x} \lim _{ \delta x \to 0 } \frac{ a^{ \delta x } - 1 }{ \delta x} .

So the gradient is merely a multiple of the original function.

The number e

The number "e" arises a lot in mathematics, and can be calculated:

 e = \lim _{n \to \infty} \left( 1 + \frac{1}{n} \right) ^{n} .

It has a special property in the context of this differential method, and to discover this it is useful to consider the factor of multiplication of "e" that there would be (using the previously defined formula) for the derivative of  e^{x} . Calculating this will give something that tends to 1, and therefore:

 \frac{d}{dx} e^{x} = e^{x}

This function is the only function whose derivative is itself.

Another definition of this function is used:

 exp : x \mapsto e^{x} .

Index laws can often be used to differentiate the slightly more complicated functions, for example:

 \frac{d}{dx} e^{n + x} = \frac{d}{dx} e^{x}e^{n} = e^{x + n} .

(Alternatively, the method discussed in the previous section of the notes can be used).

As differentiation and integration are opposites, it is simple to see the integral of the exponential function:

 \int e^{x} \,dx = e^{x} + C .

Application to exponential growth and decay

The natural logarithm is often used in mathematics, this is the logarithm with base "e"; it is used due to the special properties that it has.

 y = e^{x} \Leftrightarrow \ln{y} = x .

As it is usual to differentiate using "e", it might be necessary to write the equation which models the exponential growth using this constant as a base. This is easier to do (often) using the logarithmic form:

 y = ae^{ct} \Leftrightarrow \ln{y} = \ln{a} + ct

So, in this case the gradient of the graph of  \ln{y} against "t" is "c".

Differentiating the natural logarithm

The exponential function (with base "e") is the inverse function of the natural logarithm, and as they are both one-one, they are reflections of each other in the line  y = x with their natural domain.

Consider a point (a, b) on the curve  y = e^{x} ; this can be represented also as  \left( a, \ e^{a} \right) .

Due to the reflection, the corresponding point on the natural logarithm curve is:  \left( e^{a} , \ a \right) .

Consider any line  y = mx + c , and a corresponding line which is the reflection in the line  y = x .

Hence:  x = my + c \implies y = \frac{ x - c }{m} .

Hence the new gradient is  \frac{1}{m} .

Hence, the gradient of the given point on the logarithmic curve is  \frac{1}{e^{a}} . This is true for all values of "a" on the curve, and therefore:

 \frac{d}{dx} \ln{x} = \frac{1}{x} .

The reciprocal integral

Integrating the powers of "x" is a basic task, however there is a problem with a certain power:

 \int \frac{1}{x} \,dx .

Using the rule of:

 \int x^{n} \,dx = \frac{1}{n + 1} x^{n + 1} + C

Produces a problem, as there is division by zero for this value. Again, results from differentiation are helpful; due to the relationship between differentiation and integration, it is simple to say:

 \int \frac{1}{x} \,dx = \ln{x} + C .

Extending the reciprocal integral

The natural logarithm is not defined for values  x \le 0 , however,  \frac{1}{x} < 0 is defined.

Testing the derivative of the natural logarithm of a negative "x" can see if this method of making all negative values positive (by changing signs):

 \frac{d}{dx} \ln{-x} = -1 \times \frac{-1}{x} = \frac{1}{x} .

Hence the modulus function can be used:

 \int \frac{1}{x} \,dx = \ln{ | x | } + C .

The derivative of  b^{x}

Before it was seen that the derivative of the general exponential function was  cb^{x} where the constant "c" was to be determined.

Consider:

 b^{x} = \left( e^{ \ln{b} } \right) ^{x} = e^{x \ln{b}}

Hence:

 \frac{d}{dx} b^{x} = \ln{b} \times b^{x} .

Irrational indices

Core 2 does not consider the irrational indices, however they can be considered.

Using the reciprocal integral as a definition of the natural logarithm, only an irrational limit of integration is needed which is acceptable. Due to the fact that the product of two reals is real, and also that the exponential function is defined over the reals, there is always a real value for an irrational index.

Discussions Toggle
St Andrews Applicants 2012
started by: such_a_lady
forum: St Andrews University
replies: 1370
last post: 1 Minute Ago
Healthy New You: Your Change For Life #2
started by: xoxAngel_Kxox
forum: Fitness
replies: 179
last post: 2 Minutes Ago
A2 english language investigation
started by: keepinorder
forum: English
replies: 1
last post: 2 Minutes Ago
How effective is the gcse Maths Watch CD?
started by: Vorsah
forum: Maths Exams
replies: 1
last post: 2 Minutes Ago
God cannot know everything. Carnal love, reproduction or sex.
started by: Greatest I am
forum: Religion
replies: 35
last post: 3 Minutes Ago
What about medicine makes it so difficult?
started by: Reina
forum: Medicine
replies: 11
last post: 3 Minutes Ago
When faced with a medical query, do you Google it or see a Doctor?
started by: ROYP
forum: Advice on Everyday Issues
replies: 32
last post: 3 Minutes Ago
KCL to finally offer a semi-economics related degree
started by: .ACS.
forum: Economics
replies: 18
last post: 3 Minutes Ago
Nursing offers and interviews 2012
started by: AmyAnna
forum: Healthcare and Nursing
replies: 139
last post: 4 Minutes Ago
When is it 'à la' and when is it 'de' in French?
started by: TheWantedGuy
forum: Foreign Languages
replies: 10
last post: 4 Minutes Ago
Southampton BM6 2012
started by: xcoral23
forum: Medical Schools
replies: 1848
last post: 4 Minutes Ago
City of Westminster college (vs William Morris vs City of Islington)
started by: Saif95
forum: Secondary School, Sixth Form and FE College
replies: 2
last post: 5 Minutes Ago
Medicine Stalking Thread 2012 - NO DISCUSSION
started by: Penguinsaysquack
forum: Medicine
replies: 1660
last post: 5 Minutes Ago
Do people celebrate after finishing their A Levels?
started by: Aussie-Pom
forum: A-Levels, ASs, A2s, VCEs
replies: 9
last post: 7 Minutes Ago
What is your dream job?
started by: Roberto-MOr
forum: Careers sectors and Employment
replies: 104
last post: 7 Minutes Ago
Becoming religious without believing in God?
started by: beepbeeprichie
forum: Religion
replies: 3
last post: 8 Minutes Ago
Your Favourite Football position?
started by: hbk4894
forum: Football
replies: 44
last post: 9 Minutes Ago
Who are your idols from history?
started by: Gurmeet.Kapoor
forum: History
replies: 70
last post: 10 Minutes Ago
a levels - again...
started by: Blashnet
forum: A-Levels, ASs, A2s, VCEs
replies: 4
last post: 10 Minutes Ago
Durham Offers/Rejection Thread
started by: student1234567891
forum: Durham University
replies: 385
last post: 10 Minutes Ago
Article Updates Toggle
Contact Us | Site Rules | Staying Safe on TSR | Advertising | Staff Blog | Essays & Coursework | Terms & Conditions | Top
Customise your TSR | Life Advice | Hobbies and Interests | Debate and Current Affairs | Study Help | University and University courses
Universities and HE Colleges | Careers, Employment and Gap Years | General Discussion

Customise your TSR