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STEP III 1997 question 3 solution
From The Student RoomTSR Wiki > Study Help > Subjects and Revision > Mathematics > STEP > STEP III 1997 question 3 solution The roots of the polynomial
Dividing by
as required. Next part: Embedding the problem in the Argand plane, we can let But then, let Let the point Then the coordinates of Now we have
But
(This is basically the horizontal bit of the vector identity proved in the last part) So
as required. Solution by ukgea |










are
and hence the polynomial can be written.
.
, and converting the formula for the sum of a geometric sequence into and actual sum of a geometric sequence, we get
be represented by the complex numbers
, respectively. the point O then corresponds to the complex number 0.
in the above proved formula. Then, the LHS becomes zero, and the sum in the RHS is precisely the sum of the position vectors of
have coordinates
, the point
have coordinates
.
for
are given by
.





