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STEP III 2007 question 6 solutionTSR Wiki > Study Help > Subjects and Revision > Mathematics > STEP > STEP III 2007 question 1 solution Firstly, and similarly for q. Thus we have and the first result follows. Then, note that if or Either way, we have and thus from which it follows that as required. For the next part, we have in the case Multiplying the first and the third equations, and then dividing by the second, we get there are obviously two distinct In this case, any For larger n, we have exactly the same sitution as in n = 3 when n is odd (you can use the same reasoning, just alternatingly multiply and divide all the equations together) and as in n = 4 when n is even (again the same reasoning, the last equation can always be obtained by alternatingly multiplying and dividing the first ones together. Solution by ukgea. |