got it, thank u so much.

yes the forum rules do apply but this was necessary in my opinion as many people were explaining and she couldn't work it out see :

'Do not post full solutions unless absolutely necessary. Instead, try to guide the person asking towards working out the answer themself.'

many have guided her but it didnt work so i posted a solution with the working out.

Only use the constant c when there is no limits.

Part c, refers to the displacement of P from 10s to 20s. Remember SuVAt (constant acceleration is the key word). The question has provided you with the velocity, therefore when integrating the velocity you obtain the displacement S=[ - 800/t - 2t ] to be evaluated from 10s to 20s .

Nw happy to help. Good luck for your exams I’m sure you’ll smash them 🤟

I need to calculate the returns of the market index and the stock ,then its asking for standard deviation and average . I am so confused ? how do i do this

company 500 Index 3 mnth Treasury bill yield (rate of return)

122.01 1597.57 0.04%

122.75 1630.74 0.05%

118.34 1606.28 0.04%

125.89 1685.73 0.04%

120.43 1632.97 0.02%

121.5 1681.55 0.05%

119.96 1756.54 0.07%

122.44 1805.81 0.07%

124.91 1848.36 0.04%

111.63 1782.59 0.05%

115.33 1859.45 0.05%

118.91 1872.34 0.03%

125.52 1883.95 0.03%

122.79 1923.57 0.04%

130.55 1960.23 0.03%

129.24001 1930.67 0.03%

129.45 2003.37 0.02%

119.32 1972.29 0.02%

119.95 2018.05 0.02%

108.87 2067.56 0.03%

112.18 2058.9 0.03%

102.53 1994.99 0.02%

106.68 2104.5 0.03%

104.98 2067.89 0.02%

111.06 2085.51 0.02%

103 2107.39 0.02%

96.47 2063.11 0.03%

88.48 2103.84 0.07%

80.99 1972.18 0.02%

78.88 1920.03 0.02%

90.88 2079.36 0.12%

91.32 2080.41 0.23%

89.96 2043.94 0.26%

Nevermind, I used the wrong value.

I think you're correct. The answer is everything in the (b^2-ac) bracket to be divided by a^2 in the form of a fraction, yeah, so I think you are right. It's been so long since doing the basic fraction stuff that I've forgot the foundations needed to do the harder A-level questions. I keep making these type of easy mistakes

the sin part is right, but using the sin rule to get the angle based on the diagonal of the forces parallelogram is much neater/easier? Similarly the cos rule allows you to get an exact answer of 7.

You've got the diagram about right. Just resolve 7N horizontally and vertically.

The vertical reaction, which determines the horizontal friction, will be

mg - 7sin(30)

The rest should follow?

Ok thank you so much ! I’ve tried some practice questions in the revision guides but then I try them out of the textbooks and they’re completely different levels of complexity and understanding so it’s disheartening when I ace the revision guides questions but then completely fail the text books one, but I’ll keep trying

Hopefully the 6 makes sense, it must obviously be outside the circles.

When it says '30 have a brother' it's not as specific as saying '30 have ONLY a brother', this means that these 30 people, while they have a brother, some of them can also have a sister as well.

So there is no way to know what exactly this split is. But you're given more information regarding sisters. Same issue occurs, you don't know how many of these also have a brother.

The number of people who have BOTH, is denoted by and can be found by simply calculating .

We know that since this is the number of people who have a brother, similarly . Then is the total number of people who have either a brother, a sister, or both. This can simply be found by considering the fact that 50 people are interviewed, and only 6 dont have either. This means the rest must have either a brother, a sister, or both.

I don't have the familiarity with the new AQA A Level as I did with the old one, so please don't take my answers as definitive. But for the older version of this course, you were only expected to know the gradient of the curve at the pole, and only to use non-negative values of r. The first point may have changed, but I would be very surprised if the second one has.

Much better to rearrange the equation so that, in this case, the factor cos@ sits ahead of a term in brackets and the right hand side is equal to zero. Given that the right hand side = 0, you can then state that either cos@ = 0, or the (bracketed expression) = 0. The "book" solution you posted does it this way (except that they made the left hand side = 0 but I'm sure you get the concept).

you need to know how to formulate a linear programming problem, as you'll have to do that from some of the new algorithms you do, but you don't actually solve any of those so thankfulllyyyy no graphical methods/ simplex in D2 :)

Buy this revision guide on amazon. It has notes in it and worked examples. The notes are all condensed. It saves you having to make notes when you could be spending your time doing practice questions. https://www.amazon.co.uk/New-Level-M...s%2C152&sr=8-1

hi, I would like to know whether AQA functional skills maths level 2 is easier than Edexcel maths level 2? which exam board would be good for me.

I tried city and guilds functional skills and hated it so trying another exam board is ideal for me but dont know which to go for.

thanks

not_XIX_forever

I am in also dire need for the OCR MEI B Maths resources especially for the statistics.

Sure, id expect the answer may be somewhere inbetween. Saying the numbers are the same shows little. However if you said something about the functions being inverses, the derivatives being reciproca l, then that's clear info to get marks for. However, do check the mark scheme.

Here's the second chapter(Atoms and Electrons). The first chapter is just 10 pages on practical skills.

file:///C:/Users/user/Downloads/Atoms%20and%20Electrons%20Chapte r.pdf

Have you been taught the formula relating the circumference of a circle to its radius or diameter? It'll be in your notes somewhere.

i get it by what do you do with the 1+ at the beginning. do you just add 1 to the final answer?

Thank you

Do you have a question at all? If you want to know about the Unitary group the wiki for it gives an introduction. In regards to dynamical symmetries https://www.worldscientific.com/worl...s/10.1142/7548 is the only non-research book I can find on it, it may be worth a look. I'd also look at the references on the wiki page as they will probably give you the best overview.

Yeah thats the answer! 😅

I get it now

Thanks alot!

could you please send it to me too?

what paper is this

Was the answer 107.5m

what level of exam are you talking about. at gcse they generally gave you working marks for the longer questions, but if your answer is far off they may feel the workings marks arent justified --- this causes successful remarks sometimes

Do you mean the ones linked off here? https://www.thestudentroom.co.uk/sho...d.php?t=367072

If so, they appear to be available for download (they're word files). What's the problem you're having?

Is it free ? I so I am interested

Differentiating (sinx * cosx) in one go is a bit ugly, how about looking for something you could substitute instead, there are some simple trig identities that would help. Also get that 2 from the 2*y on the LHS factored out and moved to the right just to tidy things up. That should give you something a bit more obvious to work with.

Clearly you need to use F=ma. I presume you've already drawn a diagram for the situation and marked on forces.

If you apply F=ma to the whole thing, car and trailer, you will have two unknowns "F" and "a" (acceleration), so notimmediatelyhelpful.

If you apply it soley to the trailer you only have one unknown, the acceleration. So, start there to work out the accleration, then apply it to the whole lot, to find F.

ok, thank you.

thanks for the help

Ratios, algebra, geometry, problem solving

It has elements of each of these. Tbh, you just need to think about what each figure is telling you and how you combine.

The left figure says 1 length = 4 width

The right one says 1 length + 1 width = 10

What you need to practice (not watch) depends on which bit you find difficult.

The square root symbol only applies to the positive square root, so every time you write it, it’s good to consider what you mean, and whether it’s actually correct.

Eg. X^2=4 would have 2 solutions

X=root4 would have 1

So when you’re doing algebra, it’s important to think about whether you have added/removed solutions at each stage of your working.

It can also cause some issues when working with inequalities, and you always need to be careful if you square both sides of an equation.

Does this answer your question a bit?

Something like partial derivatives and chain rule

https://study.com/academy/lesson/the...rivatives.html

but how do you know which two side lengths are equal?

Hope this helps

I have completed this question using a Venn Diagram. I also worked out the middle intersection labelling it as "x" initially.

See the picture for the workings and answers!

Hope this helps!

Yep, you are right again. I guess I was really lucky to have a brilliant maths teacher who could teach the lot well, including S level. As a tutor I expect to teach any maths (including further), chemistry or physics topic that students throw at me, and do it off the top of my head. But then I'm an old fossil.

Duplicate thread

A-level further maths FS1 statistics

dont worry though

i know the formula

thanks for you help

cant seem to delete. i click on edit and isnt letting me

Hi!

I am going to sit my Maths A level this year and i use mainly these two websites for all my maths revision;

www.physicsandmathstutor.com ... so many questions on here, all ordered into mechanics/stats/pure

https://www.examsolutions.net/a-level-maths/aqa/ these are worked questions, so if youre stuck, just watch the guys youtube videos under the questions :)

10% didn't have the dessert, therefore 55% had both the main meal and the dessert.

Thanks a lot to correct me. Now I got the correct answer according to the book.

If you need help to do a simple derivative definition-type for an assignment, then unfortunately your problems are probably more fundamental than simply completing this assignment.

Edit: 4 months ago you were asking questions which involved odes/wronskians etc. Something just ain't right.

The weights of a group of mice, D grams are modelled as D~N (u,25). If 97.5% of the mice weigh less than 70 grams find u. Please help

Does anyone have an a-level mathswatch login I could use?

I was also struggling for resources for decision as exam solutions has not uploaded any videos. Integral maths /Further Maths support programme has some very good videos. You should be aware of the login details required given that you are studying FM but if not, it is likely your school is subscribed to it so they can given you the login details.

Uploaded the 2019 version. :)

Okay I get how the cast diagram works — and it is so much quicker/easier to use

Send the link

If your internal, I assume you have a teacher. It’s quite difficult to find the markscheme for 2019 because it’s normally not publicly released till next year of when it was sat. Maybe ask your teacher if you could have access to it because they are your best shot and it’s hard for students to access the paper, unless they remember it, even more so for the markscheme

Hello Pangol, thank you very much for your reply. That is so peculiar I intended to post the thread in the physics forum, I think that it changed automatically when I was typing in the 'ask a question' space.

Anyhow, yes thank you for spotting that, I think I got carried away and forgot to refer back to the question. In which case the solution to question a would be option 2, since if r=1.08, d=2r; d=2*1.08=2.16 mm.

D: Right, so if the typical value is to the nearest power of 10 would the answer be C. ~1 ms^-1?

F: Sorry, another silly mistake. 0.8*60=48 C

Q=n*e

n=Q/e

n=48/(1.6*10^-19)

n=3.0*10^20 (answer 2)

H: I did not think that my answer corresponded to one of the options since I believe that I calculated a solution in amps, being 9.8304*10^-6 A which is 9.8304*10^-3 mA.

Converting mA to uA: 9.8304*10^-3 mA = 9.8304 uA ~ 9.8 uA (answer A)

I think that I had just forgotten to convert to mA, and uA after calculating in A so I thought that I had arrived at the incorrect answer.

Thank you very much for your help I really appreciate it ✌️

You could rewrite this as (2^-1)^-3/2

Multiplying the powers would give us 2^3/2

This means that we are cubing 2, then square rooting it <--------- (Think the bottom is the root (like a flower), and the top is the power)

so 2^3 is 8, therefore the answer is sqrt(8)

This can then be simplified down to 2*sqrt(2)

Does anyone know where AEA Maths past papers from before 2002 are? Someone was saying there were ones from the 90s online

Not a thorough proof, but its a triple nested loop

https://stackoverflow.com/questions/...hall-algorithm

so O(n^3)

Does anyone know the JMC kangaroo 2015?

Good. Now start thinking of some examples.

Let be a set, and A and B subsets of . Consider the sigma algebra generated by A and the sigma algebra generated by B. These are both very simple finite sigma-algebras. What happens if you take the union of these?

Now start thinking about how many elements there can be in a finite sigma-algebra...

(N.B. the finiteness of a sigma-algebra refers to the number of sets in the sigma-algebra, not to whether the underlying set is finite).

that makes more sense now thanks