The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

Unusual Integral - Confused :S please help!!

Can you help me with this

I am seriously confused... Thanks

∫1.50dx9−x2\int_{1.5}^{0}\frac{dx}{\sqrt{9-x^2}}
Reply 1
Avatar for DFranklin
DFranklin
18
You need a trig substitution.

Spoiler

Reply 2
Avatar for JGR
JGR
9
Original post by asem93

Original post by asem93
Can you help me with this

I am seriously confused... Thanks

∫1.50dx9−x2\int_{1.5}^{0}\frac{dx}{\sqrt{9-x^2}}


As a hint, try differentiating arcsin x and see what you get.
Reply 3
Avatar for james.h
james.h
11
There's a square root on the bottom that doesn't look nice, so look for a substitution to turn 9−x29-x^2 into a square. :yep:

Remember that the stuff in the square root is positive for real solutions, so xx only takes values between -3 and 3 inclusive. :smile:

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you