The Student Room Group

Nitration of Methylbenzene

It's not covered in the book, so I took a crack at guessing the reaction equation, as I'm sure I have to know it. Can you tell me if this is correct?

C6H5(CH3)+3HNO3Heated under reflux/30conc.H2SO4C6H2(NO2)3CH3+3H2OC_6H_5(CH_3) + 3HNO_3\xrightarrow[\text{Heated under reflux}/ 30^{\circ}]{conc. H_2SO_4}C_6H_2(NO_2)_3CH_3+3H_2O
Original post by ViralRiver
It's not covered in the book, so I took a crack at guessing the reaction equation, as I'm sure I have to know it. Can you tell me if this is correct?

C6H5(CH3)+3HNO3Heated under reflux/30conc.H2SO4C6H2(NO2)3CH3+3H2OC_6H_5(CH_3) + 3HNO_3\xrightarrow[\text{Heated under reflux}/ 30^{\circ}]{conc. H_2SO_4}C_6H_2(NO_2)_3CH_3+3H_2O


Assuming it goes all the way to trinitro..

yes :smile:
Reply 2
Perfect, thank-you :smile: .
effectively yes, but the reaction is a lot more complicated than that. The H2SO4 reacts with the HNO3 to give NO2+ ions that substitute onto the benzene ring.
Reply 4
Yeah it looks right. Just remember the intermediate of N O2+.

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