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integration help :(

integrate;
x(sin x + cos x) dx:confused:
Original post by Bueno93
integrate;
x(sin x + cos x) dx:confused:


Are you familiar with Integration by parts?
udvdxdx=uvvdudxdx\displaystyle\int u\frac{dv}{dx}dx = uv - \int v\frac{du}{dx}dx
Choose u=xu=x and dvdx=sinx+cosx\frac{dv}{dx}=\sin x + \cos x.
(edited 13 years ago)
Reply 2
Use integration by parts, with u=x, dvdx=sinx+cosxu=x,\ \frac{dv}{dx}=\sin x + \cos x.

EDIT: Beaten by Farhan!
Original post by Farhan.Hanif93
Are you familiar with Integration by parts?
vdudxdx=uvvdudxdx\displaystyle\int v\frac{du}{dx}dx = uv - \int v\frac{du}{dx}dx


Typo in there Farhan. :smile:
Original post by Get me off the £\?%!^@ computer
Typo in there Farhan. :smile:

Well spotted.

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