Okay quick question in the textbook, example 8 page 69, shows that the F used in work done is the resultant force. however on example 2 on page 64, for F, that isn't the resultant force? I'm confused. (as in they didn't do 96=(F-R)x12
This links to question 3 in the Jan 09 paper, they had a positive force, and a large resistive force (and acceleration) but when asked to calculate the work done against friction, the mark scheme just shows friction x distance (it doesn't seem to take into account the other force at all!)
Okay quick question in the textbook, example 8 page 69, shows that the F used in work done is the resultant force. however on example 2 on page 64, for F, that isn't the resultant force? I'm confused. (as in they didn't do 96=(F-R)x12
This links to question 3 in the Jan 09 paper, they had a positive force, and a large resistive force (and acceleration) but when asked to calculate the work done against friction, the mark scheme just shows friction x distance (it doesn't seem to take into account the other force at all!)
Please help D: i'm so confused now lol
A. Work done against friction.
Distance x friction x R = 50 x 4/7 x 10g = 2800 j
B. You can use F = ma to get acceleration then use a suvat.
We don't have anyone doing M2 this session so I will not be able to get hold of the paper immediately; as soon as I get the paper I will do some solutions.. could be on the weekend but may not be until Monday.
I haven't taught it for 6/7 years or so. I am thinking of giving myself an A2 FM group next year as I am getting rusty.
If your M1 knowledge is sound, M2 really isn't that much more difficult.
On the CoM questions, check carefully it isn't a shape made from rods rather than a solid. Also practise the toppling/hanging parts, they always seem to cause the most problems (is toppling on M2?)
Ahhh thanks, completely forgot about toppling, have never seen a question with it. On that note, I have time for about 3-4 papers before I'm off, so what would you suggest are the hardest?