Using your formula, x, the distance between X and Y is 1.5 wavelengths, so put x = (3/2) lambda in it and you get phi = 3 pi
Original post by Stonebridge
Using your formula, x, the distance between X and Y is 1.5 wavelengths, so put x = (3/2) lambda in it and you get phi = 3 pi
Using your formula, x, the distance between X and Y is 1.5 wavelengths, so put x = (3/2) lambda in it and you get phi = 3 pi
But what I read was that x IS always less than wavelength, and when any number of wavelengths come into the value of x we eliminate that number of wavelengths. Like for example let us take wavelength as 1, then distance between X and Y is 1.5, so eliminating one gives us 0.5 to be used as x? OR is my concept wrong? :s
Two points on a wave can be any number of wavelengths apart, and phi can be any value.
I think what you are thinking of is the fact that, as the cycle just repeats itself, a phase difference of 1.5 wavelengths amounts to the same displacement as a difference of 0.5
But a point at a phase difference of just pi would not be at the same place on the graph/wave as Y, though it is at the same distance below the axis, as will be the points at 2.5, 3.5 4.5 etc.
I think what you are thinking of is the fact that, as the cycle just repeats itself, a phase difference of 1.5 wavelengths amounts to the same displacement as a difference of 0.5
But a point at a phase difference of just pi would not be at the same place on the graph/wave as Y, though it is at the same distance below the axis, as will be the points at 2.5, 3.5 4.5 etc.
Original post by Stonebridge
Two points on a wave can be any number of wavelengths apart, and phi can be any value.
I think what you are thinking of is the fact that, as the cycle just repeats itself, a phase difference of 1.5 wavelengths amounts to the same displacement as a difference of 0.5
But a point at a phase difference of just pi would not be at the same place on the graph/wave as Y, though it is at the same distance below the axis, as will be the points at 2.5, 3.5 4.5 etc.
I think what you are thinking of is the fact that, as the cycle just repeats itself, a phase difference of 1.5 wavelengths amounts to the same displacement as a difference of 0.5
But a point at a phase difference of just pi would not be at the same place on the graph/wave as Y, though it is at the same distance below the axis, as will be the points at 2.5, 3.5 4.5 etc.
Hmm, though it's a bit difficult to understand but I'll try to remember it. Thanks.
Quick Reply
Related discussions
- Physics question ripples
- Does this engaa waves question even make sense??
- Help on this waves/phase difference question?
- Physics question phase difference
- interference
- Answering Questions: What is CDIO?
- Mechanics A Level Maths Problem
- Medicine @UCLAN
- AQA A Level Physics Waves Question
- biology question
- Confused about my gender identity
- How can 2 waves be in phase if they have different amplitudes?
- Physics AS help
- RAF Halton pay/ deductions
- Help mechanics urgent
- Finance MSc student graduating 2024 (struggling to get an internship)
- Urgent mechanics question!!
- RAF Halton - Phase 1 Training (Week 1-10) Breakdown
- Formal lab report
- Can anyone help with this SUVAT A-level question?
