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Algebraic Manipulation

Hi,

I am struggling to rearrange the equation for A1=B11B2A_1=\dfrac{B_1}{1-B_2} into B1=A11+A2B_1=\dfrac{A_1}{1+A_2}. I also have the information that A2=B21B2A_2=\dfrac{B_2}{1-B_2} which I know how to translate into B2=A21+A2B_2=\dfrac{A_2}{1+A_2}. Could someone please show me how to do this. Thanks.
(edited 13 years ago)
Reply 1
Well, take B2=A21+A2 B_2=\dfrac{A_2}{1+A_2} and substitute into A1=B11B2A_1=\dfrac{B_1}{1-B_2} to give A1=B11A21+A2A_1=\dfrac{B_1}{1-\dfrac{A_2}{1+A_2}}.

Now multiply by the denominator and rearrange:
B1=A1A1A21+A2=A1(1+A2)1+A2A1A21+A2=A1+A1A2A1A21+A2=A11+A2B_1=A_1-\dfrac{A_1A_2}{1+A_2}=\dfrac{A_1(1+A_2)}{1+A_2}-\dfrac{A_1A_2}{1+A_2}=\dfrac{A_1+A_1A_2-A_1A_2}{1+A_2}=\dfrac{A_1}{1+A_2}.
Reply 2
Original post by kfkle
Well, take B2=A21+A2 B_2=\dfrac{A_2}{1+A_2} and substitute into A1=B11B2A_1=\dfrac{B_1}{1-B_2} to give A1=B11A21+A2A_1=\dfrac{B_1}{1-\dfrac{A_2}{1+A_2}}.

Now multiply by the denominator and rearrange:
B1=A1A1A21+A2=A1(1+A2)1+A2A1A21+A2=A1+A1A2A1A21+A2=A11+A2B_1=A_1-\dfrac{A_1A_2}{1+A_2}=\dfrac{A_1(1+A_2)}{1+A_2}-\dfrac{A_1A_2}{1+A_2}=\dfrac{A_1+A_1A_2-A_1A_2}{1+A_2}=\dfrac{A_1}{1+A_2}.


This is the gift that keeps on giving. Thanks for your input, Sonny Jim. You've just saved my bacon. <3

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