The Student Room Group

I have a simple puzzle which I doubt anyone here will be able to solve.

Scroll to see replies

Reply 20
Does it count as sitting next to the same 2 neighbours if you only sit next to one of the two?
Reply 21
They all have an empty seat between them.
Reply 22
They lie on the chairs.
Reply 23
Original post by Core
Does it count as sitting next to the same 2 neighbours if you only sit next to one of the two?


it does not count.
Reply 24
ABCDEFG, ACBEDGF, CABFDGE, Thats as far as i am going. 12 to go?
Reply 25
Original post by Core
They lie on the chairs.


And I suppose they drink whine through their noses as well.
Reply 26
there should be 42 combinations. or 14 is that right? Is it to do with binomial expansion or exponential?
Reply 27
Original post by Core
there should be 42 combinations. or 14 is that right? Is it to do with binomial expansion or exponential?


Nothing to do with binomial, sequences actually- I think. There are thousands of combinations.
Original post by Stratos
It's simple just kill them all of until only 1 survives.


Kind of like a cross between battle royale and come dine with me? :biggrin:
Reply 29
I think:

On the first day have ABCDEFG going around the table, then cycle ADE to give 2 more. Then BEF, CFG, DGA, EAB, FBC and GCD, each gives 2 new combinations (excluding the orginal order from each rotation). This give 7*2+1=15 seatings.
(edited 12 years ago)
Reply 30
Original post by Miss_Scarlett
Kind of like a cross between battle royale and come dine with me? :biggrin:


It's the secret supper club!

Quick Reply

Latest