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Fp1 Help Series Question

teacher gave me the jan 11 paper to try and there's a question on series that i'm struggling with (the part I can't do isn't really related to that topic area however).

Its part 8c, just not sure how to solve the cubic or maybe i'm just over thinking. Thaks for any help!

Reply 1
Avatar for vc94
vc94
12
8c) If you continue the iteration in part (a) this will give the solitary real root.
So N will be the lowest integer greater than this root.
Reply 2
Avatar for Naathan_b
Naathan_b
OP
6
Original post by vc94
8c) If you continue the iteration in part (a) this will give the solitary real root.
So N will be the lowest integer greater than this root.


So am I working out the value of x3?? I got 45.8 so does that mean N is 45? or am I doing that completely wrong, I just dont understand why that would be what you have to do?? Sorry if i'm being a real pain.
Reply 3
Avatar for vc94
vc94
12
You have a cubic graph passing through root 45.8.
The inequality is >0 so you're interested in the part above the y-axis. So the solution is N>45.8 hence N must be 46.
Reply 4
Avatar for Naathan_b
Naathan_b
OP
6
Original post by vc94
You have a cubic graph passing through root 45.8.
The inequality is >0 so you're interested in the part above the y-axis. So the solution is N>45.8 hence N must be 46.


ahhh now I get it, thank you!!

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