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STEP Q - got it right, but is it right? Watch

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    OK STEP I 2004 question 3 (ii) asks you to factorise 6y^3-y^2-21y+2x^2+12x-4xy+x^2y-5xy^2+10 into 3 linear factors. I did it all and got the factors as:

    (y+2)(3y-x-5)(2y-x-1) which is right however in the answers they have:

    (y+2)(x-3y+5)(x-2y+1) it's the same thing basically, but will I get the marks for writing it in my form?
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    (Original post by Ultimate1)
    OK STEP I 2004 question 3 (ii) asks you to factorise 6y^3-y^2-21y+2x^2+12x-4xy+x^2y-5xy^2+10 into 3 linear factors. I did it all and got the factors as:

    (y+2)(3y-x-5)(2y-x-1) which is right however in the answers they have:

    (y+2)(x-3y+5)(x-2y+1) it's the same thing basically, but will I get the marks for writing it in my form?
    Same thing, you'll get the marks unless the examiner is a complete bafoon.
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    Yes, it's fine.
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    Of course you will. They're equivalent.
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    (Original post by icedragon)
    Same thing, you'll get the marks unless the examiner is a complete bafoon.

    (Original post by Zuzuzu)
    Yes, it's fine.

    (Original post by Farhan.Hanif93)
    Of course you will. They're equivalent.
    Thanks!!
 
 
 
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