im such an idiot man , when it sed calucltae r , i didnt know it was the gradient , i did it the long way , E= IR+Ir, i could have saved soo much time

Reply 227

Naum

Original post by Limitless

Couldn't think of a proper comeback eh! Oh well... :rolleyes:

What do you mean comeback lol? I'm not here to have a verbal war with you or anything, calm down.

Reply 228

ciarangc

I really think the mark boundries will be quite low. Does anyone thing ill get any marks for this. This is for the calculating the internal resistance "So for some reason i used 1.5 as the emf (1 mark lost) and again for some reason i calculated the lost volts as :1.5v-1.4V = 0.1V. I then read this value off the graph and I got A Current value of 0.3. R=V/I so R=0.1/0.3 so i got an answer around 0.33 ohms, will i get anything?

Reply 229

Brasileira

Original post by TimetoSucceed

what was the gradient for on the graph? =/ i probably fukd up big time

I'm almost definite it was 0.45 ohms.

I had (1.52-0.09)/3.20 = 0.45 :smile:

Reply 230

tuckaa

Original post by Limitless

Depends on the grade I get in August. If it is a B I'm requesting a remark. I asked for my paper back for the Jan11 paper there are like 6 marks the examiner never gave me and with those 6 I could have moved from a C to an A. I can't get a remark for that paper now I'm well pissed off.

This.

In jan i got my paper back, about 5 marks marked very very harshly, but by then you cant get it remarked.

They should be more carefully moderated, especially when theres four marks between whole grades.

Reply 231

ciarangc

I knoiw, you are right. But will i get anything for my answer?? :smile:

Reply 232

Brasileira

For the charge/mass ratio... I did

2 x 1.60x10^-19 (electron charge)/ 4 x 1.67x10-27 (mass of nucleons)

which gave me 4.8x10^7, I think.

Reply 233

TimetoSucceed

7

fuk my life, effort and no reward, whats the point?

Reply 234

Limitless

Original post by tuckaa

This.

In jan i got my paper back, about 5 marks marked very very harshly, but by then you cant get it remarked.

They should be more carefully moderated, especially when theres four marks between whole grades.

I know. There shouldn't be a need to remark. They should just mark it properly the first time. Then we have to pay for the remark ourselves yes you may get refunded if you go up a grade in that paper but what if you go up by a few marks and your overall grade increases. You have to pay for the remark and get no refund.

Original post by Naum

What do you mean comeback lol? I'm not here to have a verbal war with you or anything, calm down.

So calling me a dumbass was just friendly talk?

Reply 235

TimetoSucceed

7

when you retake in jan when do you get your results? and you can't remark?

Reply 236

ciarangc

I really think the mark boundries will be quite low. Does anyone thing ill get any marks for this. This is for the calculating the internal resistance "So for some reason i used 1.5 as the emf (1 mark lost) and again for some reason i calculated the lost volts as :1.5v-1.4V = 0.1V. I then read this value off the graph and I got A Current value of 0.3. R=V/I so R=0.1/0.3 so i got an answer around 0.33 ohms, will i get anything?

Reply 237

Mr XcX

15

I am mixed now. I have got what some of Y'all are saying, just made silly mistakes.

I PRAY the grade bounaries are low.

Hopefully about 53 - 50.

Reply 238

AlesanaWill

16

Original post by Brasileira

For the charge/mass ratio... I did

2 x 1.60x10^-19 (electron charge)/ 4 x 1.67x10-27 (mass of nucleons)

which gave me 4.8x10^7, I think.

Think I got this too.

I think I may have lost a mark on the one about terminal p.d., didn't explain it very well.

Also, on the question on the back about calculating the energy dissipated per second (or whatever it was), what did everyone get? Was I right to calculate power, P = I^2r, using the internal resistance r?