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Please explain how to work this out?

3/x((x+1)^2)-x^2-1)
What are you trying to do to it?
Reply 2
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BuuTuu
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Original post by Mr M
What are you trying to do to it?


sorry, it just says simplify?
Well have you expanded the brackets and simplified that part?
Reply 4
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BuuTuu
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Original post by Mr M
Well have you expanded the brackets and simplified that part?


I don't understand how to times 3/x by (x+1)
Original post by BuuTuu
I don't understand how to times 3/x by (x+1)


Where did you get (x+1) from?

Can you expand (x+1)2(x+1)^2 ?
Reply 6
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BuuTuu
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sorry, I misread the Q, yeah--x^2+2x+1
Original post by BuuTuu
sorry, I misread the Q, yeah--x^2+2x+1


So what is (x+1)2−x2−1(x+1)^2 - x^2 - 1 ?
Reply 8
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BuuTuu
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2x
Original post by BuuTuu
2x


So what is 3x((x+1)2−x2−1)\frac{3}{x} ((x+1)^2 - x^2 - 1) ?
Original post by BuuTuu
so x^2=3/2..


Noooo .... is the big bracket on the bottom of the fraction?
Reply 11
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BuuTuu
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3/x*2x...I have no idea..
Original post by BuuTuu
3/x*2x...I have no idea..


That sounds better but could you confirm whether the big bracket is supposed to be on the top of the fraction or not?
Reply 13
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BuuTuu
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Original post by Mr M
Noooo .... is the big bracket on the bottom of the fraction?


yh, sorry I got confused--I deleted that post or I thought I had, so it would be 3/x*2x?
Reply 14
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BuuTuu
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Original post by Mr M
That sounds better but could you confirm whether the big bracket is supposed to be on the top of the fraction or not?


No, it isn't.
Original post by BuuTuu
No, it isn't.


Ok so the question is

3x((x+1)2−x2−1)\frac{3}{x((x+1)^2-x^2-1)} ?

If so, you now have 3x(2x)\frac{3}{x (2x)} ... can you simplify the denominator?
Reply 16
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BuuTuu
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3/2x^2?
Original post by BuuTuu
3/2x^2?


Yes so long as you mean 3/(2x^2).

You really need to learn LaTeX or be more careful with brackets.
Reply 18
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BuuTuu
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7
Original post by Mr M
Yes so long as you mean 3/(2x^2).

You really need to learn LaTeX or be more careful with brackets.


kk, will do thank you
Original post by BuuTuu
kk, will do thank you


you are welcome

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