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Circular motion question. !!!

I keep getting this question wrong and I have been at it for two days :angry:

The gravitational force on a satelite of mass m at a distance r from the centre of the Earth is 4.0 x10^14 (m/r^2) . Assuming that the Earth is a sphere of radius 6.4x10^3 km, find the period of revolution ( in hours) of a satelite moving in a circular orbit at a height of 3.6x10^4 km above the Earths surface.

answer is 24.1 hours any ideas on the calculation ?? much appreciated.
Original post by coco739
I keep getting this question wrong and I have been at it for two days :angry:

The gravitational force on a satelite of mass m at a distance r from the centre of the Earth is 4.0 x10^14 (m/r^2) . Assuming that the Earth is a sphere of radius 6.4x10^3 km, find the period of revolution ( in hours) of a satelite moving in a circular orbit at a height of 3.6x10^4 km above the Earths surface.

answer is 24.1 hours any ideas on the calculation ?? much appreciated.


F=mg=mrw2w=grF=mg=mrw^2 w=\sqrt\frac{g}{r}
T=2πrgT=2\pi\sqrt\frac{r}{g}
Original post by coco739

Original post by coco739
I know w^2r is acceleration and m is the mass but what is the extra w ?


typo
Original post by coco739
I know w^2r is acceleration and m is the mass but what is the extra w ?


Sorry typo :s-smilie:

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