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Reciprocal graphs

I'm unsure what 2x \frac{2}{x} would look like. I know 1x−a \frac{1}{x-a} is the translation by (-a, 0) and 1x \frac{1}{x} + a is the translation by (0, a), but would that mean ax \frac{a}{x} is the same as af(x) (stretching of the SF a in the y direction)? If someone could show me how I could stretch this curve (or what it looks like) it'd be much appreciated :tongue:
Reply 1
Avatar for TenOfThem
TenOfThem
18
type it into wolfram alpha together with 1x\frac{1}{x} and 3x\frac{3}{x} the pattern will become clear
Original post by TenOfThem
type it into wolfram alpha together with 1x\frac{1}{x} and 3x\frac{3}{x} the pattern will become clear


The curve looks like the same...it's only the axes that changes? :/
Reply 3
Avatar for TenOfThem
TenOfThem
18
Have you typed them into he same set of axes so that you can compare them
Original post by TenOfThem
Have you typed them into he same set of axes so that you can compare them


Oh right. Well 2/x is a lil further away from the x and y axis... is that right?
Reply 5
Avatar for TenOfThem
TenOfThem
18
less steep as well
Original post by TenOfThem
less steep as well


cool, thanks :smile:
Reply 7
Avatar for JOR2010
JOR2010
14
Original post by InadequateJusticex

Original post by InadequateJusticex
Oh right. Well 2/x is a lil further away from the x and y axis... is that right?


Exactly, the larger the number on top, the further away from both axes.
Reply 8
Avatar for TenOfThem
TenOfThem
18
Original post by JOR2010
Exactly, the larger the number on top, the further away from both axes.


Until infinity

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