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solve the equation x^3-5x^2-2x+24=0

solve the equation x^3-5x^2-2x+24=0

help
-2 is a root

trial and error is worth a go if you're doing exam questions
Original post by gorila7
solve the equation x^3-5x^2-2x+24=0

help


try the factor theorem. Essentially trial and error until you get your first factor. After that, give algebraic long division a go to get the other factors. Or just keep doing the factor theorem.
Reply 3
If this is the only thing you're given then it would seem that factor theorem is the only way to go. Once you find one root, you can use division to find the remaining.
use the factor theorem:smile:
Reply 5
Original post by Woffles
If this is the only thing you're given then it would seem that factor theorem is the only way to go. Once you find one root, you can use division to find the remaining.


Can you show me how to do this
Reply 6
Original post by TobeTheHero
use the factor theorem:smile:


can you show me how to do this
Reply 7
Original post by problemsolver
-2 is a root

trial and error is worth a go if you're doing exam questions


can you show me how to do this
Reply 8
First you put some numbers in to see which one(s) will give 0

Can you see why -2 was given by the posters above
Reply 9
If x=2 is a solution, then f(-2) = o since x-2=0 which makes the rest of the polynomial equal zero. Then write it as a quadratic of form ax^2+bx+c multiplied by a bracket and find the co-efficients of the quadratic. Then solve; you have your equation solved.
Reply 10
Original post by gorila7
solve the equation x^3-5x^2-2x+24=0

help


The factor theorem

If

f(x)=x35x22x+24f(x) = x^3 - 5x^2 -2x+24

then to solve f(x)=0, you use trial and error first

If

f(a)=0f(a)=0

then

(xa)(x-a)

is a factor.

Use algebraic long division to solve the equation completely after you've found 1 factor.
(edited 12 years ago)

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