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AS ocr MEI MATHS C1 13 TH JAN 2012

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Original post by Bexamoose
Yeah, can someone put the unofficial answers please! ALL of them, not individuals :smile:


Tell me the questions and I will
Some answers i got cant remember exact questions but sort of in order:
y=-x/5+31/5
1/3 and 32x^10y^-3
6n^2+12n+8
root2+23
3root6 + 12/root6 --- didnt simplify this fully
-14/3<x
9a-5/(4+a^2)
5(x+1.5)^2+0.75...0.75
area of triangle =10
midpoint =(3/2,9/2)
x co-ordinates for one of the questions on section b where 9/2,3??
and y crosses at +12 for a question?
Reply 242
for the 54+(126)\sqrt54+(\frac{12}{\sqrt6}) question I put 36+26=563\sqrt6+2\sqrt6=5\sqrt6
Original post by jordan95
for the 54+(126)\sqrt54+(\frac{12}{\sqrt6}) question I put 36+26=563\sqrt6+2\sqrt6=5\sqrt6


I got 30 as the answer to this, spent ages on it but i cant remember exacly how i did it :\ think i put the root54 over 1 then treated them as adding fractions so i got a common denominator then added them to get 30 somehow :smile:

im probably wrong though
Reply 244
Unparseable latex formula:

\setlength{\unitlength}{0.75mm}[br]\begin{picture}(60,40)[br]\put(30,20){\vector(1,0){30}}[br]\put(30,20){\vector(4,1){20}}[br]\put(30,20){\vector(3,1){25}}[br]\put(30,20){\vector(2,1){30}}[br]\put(30,20){\vector(1,2){10}}[br]\thicklines[br]\put(30,20){\vector(-4,1){30}}[br]\put(30,20){\vector(-1,4){5}}[br]\thinlines[br]\put(30,20){\vector(-1,-1){5}}[br]\put(30,20){\vector(-1,-4){5}}[br]\end{picture}

Was my original answer for the second converse statement proof question thing, then I chose left!
Reply 245
Sex of a paper! Well happy! :biggrin:
Reply 246
Original post by chris_gloyne
Some answers i got cant remember exact questions but sort of in order:
y=-x/5+31/5
1/3 and 32x^10y^-3
6n^2+12n+8
root2+23
3root6 + 12/root6 --- didnt simplify this fully
-14/3<x
9a-5/(4+a^2)
5(x+1.5)^2+0.75...0.75
area of triangle =10
midpoint =(3/2,9/2)
x co-ordinates for one of the questions on section b where 9/2,3??
and y crosses at +12 for a question?


Got all of this, but i don't remember one where the x co-ordinates were 9/2,3.
For the implies question i got i) Both imply each other ii) right implies left
.. and i got 5(x+1.5)^2+ 1.75 i think? Can't remember properly.
.. and i thought the root question was 2+root23? not root2 +23, but I could be wrong.
for the simplification i got along the lines of 3root6+2root6=5root6, (because i got 12/root6 to be 12root6/6.)
(2x-1)(x-4)(x+3) < for the fully factorised function of x? or roughly that anyway.
Centre of circle (2,0) with radius root20, y co-ordinates (0,-4) and (0,4) (+-root16)
Triangle area 10units^2
y=-1/5x + 6.2 i think, it was 31/something but i put a decimal(first question)
for the last question i got something like k=-1 and k=0 but i really didn't have much of an idea of how to do that so that's probably where i've dropped some marks.
Still thinking of other answers, if anybody could jog my memory it would be appreciated :biggrin:
(edited 12 years ago)
Reply 247
I felt like jumping off a cliff after this exam. I have made sooo many stupid mistakes :'(
Reply 248
Original post by jordan95
for the 54+(126)\sqrt54+(\frac{12}{\sqrt6}) question I put 36+26=563\sqrt6+2\sqrt6=5\sqrt6


Yeah I got 5root6 too, just in a VERY awkward method, didn't realize until I got to the answer how easily I could've actually done it :tongue:


How are you doing the root symbols and stuff? :redface:
Reply 249
Original post by Nucleo
How are you doing the root symbols and stuff? :redface:


http://www.thestudentroom.co.uk/wiki/LaTex
Reply 250
^That link should help! Thanks Xotol!

Original post by Try
Got all of this, but i don't remember one where the x co-ordinates were 9/2,3.
For the implies question i got i) Both imply each other ii) right implies left
.. and i got 5(x+1.5)^2+ 1.75 i think? Can't remember properly.
.. and i thought the root question was 2+root23? not root2 +23, but I could be wrong.
for the simplification i got along the lines of 3root6+2root6=5root6, (because i got 12/root6 to be 12root6/6.)
(2x-1)(x-4)(x+3) &lt; for the fully factorised function of x? or roughly that anyway.
Centre of circle (2,0) with radius root20, y co-ordinates (0,-4) and (0,4) (+-root16)
Triangle area 10units^2
y=-1/5x + 6.2 i think, it was 31/something but i put a decimal(first question)
for the last question i got something like k=-1 and k=0 but i really didn't have much of an idea of how to do that so that's probably where i've dropped some marks.
Still thinking of other answers, if anybody could jog my memory it would be appreciated :biggrin:


yeah i remember i got <=> and then <= for that proof question and then you could be right about the 2 +root 23 i cant remember which way round i put it, i also agree on centre (2,0) and r=root20
Reply 252
If anyone can upload the paper, i'd be more than happy to provide an unofficial mark scheme
Original post by hhh123
I also put +4, but my teacher was saying that it was something like 0.9 :/ :/


hmm well its too late now.... we cant change the past so all we can do is wait until 8th of march :smile:
Original post by laura94
I got 67, a C. I found out my aunt died on the bus on my way to the exam though so I wasn't really concentrating, and I also have anxiety so it definitely didn't help. I need an A for my uni place as well! Good luck with C3 and I hope we both get into our first choices! Have you done the C3 coursework? What did you get? Hopefully that will push up your overall C3 grade :smile:


That really sucks about your aunt, what a horrible thing to hear on the way to an exam :frown: respect for getting a C after hearing that. I got 16/18 in the coursework. I blew the 2 marks on the oral exam. Every other teacher seemed to be making sure their students got the 2 oral marks but na mine was a jerk. oh well :biggrin: how did your coursework fare?
Reply 255
Wasnt the answer to the root question 23 - root 2
I'm now depressed because I got the wrong answers for the complete the square question (I put down 5(x+15/10)^2+9.75 whereas it should've been 5(x+1.5)^2+0.75) and the area of the triangle which is 10, but I put down 20. I hope I get marks for the calculations. Damn, I can't believe I made such silly mistakes....and this was my 2nd attempt at C1 after getting a C last year. FUUUUUUUU-
Reply 257
Original post by subzero0137
I'm now depressed because I got the wrong answers for the complete the square question (I put down 5(x+15/10)^2+9.75 whereas it should've been 5(x+1.5)^2+0.75) and the area of the triangle which is 10, but I put down 20. I hope I get marks for the calculations. Damn, I can't believe I made such silly mistakes....and this was my 2nd attempt at C1 after getting a C last year. FUUUUUUUU-


Yeah youll defo get some working marks dont worry over it.. what will be will be.
And also dont worry.. its my third time resitting.
Reply 258
Can someone explain to me how they did question 10 by using the pythagoras theorem? I proved that the sides were perpendicular by using m1xm2=-1 and i got 9 square units for the area of the triangle... How did everyone get 10 :P Also does anyone remeber how many marks there were for simplifying the 56^(1/2)+(12/6^(1/2))
(edited 12 years ago)
Reply 259
Original post by Beckah-1
Can someone explain to me how they did question 10 by using the pythagoras theorem? I proved that the sides were perpendicular by using m1xm2=-1 and i got 9 square units for the area of the triangle... How did everyone get 10 :P


Once you've shown that AB and BC are perpendicular, you can use 1/2bh to work out the area.

So, you work out the distance of AB and BC (and they come to rt10 and rt40).

A = 1/2 x rt10 x rt40 = 10

You probably had an incorrect value of the distance(s).

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