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M3 Jan 2012 Edexcel

For some reasons, the other post is still closed. So I just think about starting a new one.

How do you guys think about the paper?

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Reply 1
Fairly easy tbh, apart from 2 q's, do people still remember their answers ?
Reply 2
I've done something pretty stupid. When calculating the angular velocity, I use natural length rather than extension length. Damn it. I think I lose about 2 marks for that.

One question is sqrt(5/6 * Rg), does that ring a bell to anyone?

Question about SHM, 1.8 ms^-2, 1.37 ms^-1 and 0.137s. Ring a bell?
Reply 3
I hated question 3, other than that it was one of the best M3 paper's I have seen!
Reply 4
Why did they give us a volume of revolution one, it takes so long to plug to numbers in :frown:
Reply 5
Original post by thomas93
I hated question 3, other than that it was one of the best M3 paper's I have seen!


What was it about? Is it something with v=10/x+6?

I've got 0,0125 and direction toward 0 for acceleration, and time travel is something like, well 17.8s. Ring a bell?
Reply 6
Original post by QuangHa
What was it about? Is it something with v=10/x+6?

I've got 0,0125 and direction toward 0 for acceleration, and time travel is something like, well 17.8s. Ring a bell?


Yes! Exactly what I got... Phew...
Reply 7
Q1:
lambda = 41.3952
Q2:
a) 1.8 ms/2 towards C
b) 1.3747 ms
c.) time = 0.137s
Q3
a.) -1/80 ms/2
b.) 17.8s
Q4.
a.) show that... no need for an answer
b.) omega = 4.04 rad/s
Q5.
a.) show that force = ... blah blah
b.) 9 marks differential equation where the velocity at height R above the surface was root 5gR/6 (i dont remember that one)
Q6.
a.) show that... blah blah (8 marks)
b.) costheta = 0.25 therefore v = root0.25gl or something
c.) 15/128
Q7
a. show that blah blah
b. 70.5 degrees
c. tan beta = 0.3, beta = 16.7 degrees


all of top of my head so I dont remember the exact figures

Slightly easier than previous papers with a few 'traps'


GB ------>> Very Very Rough Guess (it may vary +/- 4)

100UMS - 75
90 UMS - 69
80 UMS - 63
70 UMS - 55
(edited 12 years ago)
Reply 8
Original post by thomas93
Yes! Exactly what I got... Phew...


U remember any more question? This is as far as I got...

1) 41.4 or something, 41.3925, if I recall it correctly...

6) speed at the time string lack is 0.5*sqrt(gl), and height above b is something like... 15/128l...

7) alpha is 70.5 and beta is something like 16.7....
Reply 9
Original post by dude345
Q1:
lambda = 41.3952
Q2:
a) 1.8 ms/2 towards C
b) 1.3747 ms
c.) time = 0.137s
Q3
a.) -1/80 ms/2
b.) 17.8s
Q4.
a.) show that... no need for an answer
b.) omega = 4.04 rad/s
Q5.
a.) show that force = ... blah blah
b.) 9 marks differential equation where the velocity at height R above the surface was root 5gR/6 (i think dont remember that one)
Q6.
a.) show that... blah blah (8 marks)
b.) costheta = 0.25 therefore v = root0.25gl or something
c.) 15/128
Q7
a. show that blah blah
b. 70.5 degrees
c. tan beta = 0.3, beta = 16.7 degrees


all of top of my head so I dont remember the exact figures

Slightly easier than previous papers with a few 'traps'


F*CKING AWESOME!!!! STRAIGHT FOR ATLEAST 72/75. 1 different from u is at 4b, when I use l=0.8 instead of 1.2 (damn it... T.T)
Reply 10
Original post by QuangHa
F*CKING AWESOME!!!! STRAIGHT FOR ATLEAST 72/75. 1 different from u is at 4b, when I use l=0.8 instead of 1.2 (damn it... T.T)


Glad you did well :-)
Reply 11
Original post by dude345
Glad you did well :-)


Compare to someone who is on for 100%, nah.......

Just kidding :biggrin:
Reply 12
Original post by QuangHa
Compare to someone who is on for 100%, nah.......

Just kidding :biggrin:


Maths is like COD you don't just stop at an A* you aim for 100% ;-)
Reply 13
Original post by dude345
Maths is like COD you don't just stop at an A* you aim for 100% ;-)


I like your spirit, man :cool:.

Btw, how would u think about grade boundaries? I truly hope it will be, more or less, the same like last year.
Reply 14
Original post by QuangHa
I like your spirit, man :cool:.

Btw, how would u think about grade boundaries? I truly hope it will be, more or less, the same like last year.


Impossible to tell at that point we might need to ask a few people how they did because obviously only nerds are doing m3 in January so it might vary a lot I would still say about 63 for an A and 69 for an A* (+/- 5) hehe
Reply 15
Original post by dude345
Impossible to tell at that point we might need to ask a few people how they did because obviously only nerds are doing m3 in January so it might vary a lot I would still say about 63 for an A and 69 for an A* (+/- 5) hehe


We are nerds, then, according to your argument :-j.

I only need A*, which I think I will definitely be able to get it :biggrin:
Original post by dude345
Q1:
lambda = 41.3952
Q2:
a) 1.8 ms/2 towards C
b) 1.3747 ms
c.) time = 0.137s
Q3
a.) -1/80 ms/2
b.) 17.8s
Q4.
a.) show that... no need for an answer
b.) omega = 4.04 rad/s
Q5.
a.) show that force = ... blah blah
b.) 9 marks differential equation where the velocity at height R above the surface was root 5gR/6 (i dont remember that one)
Q6.
a.) show that... blah blah (8 marks)
b.) costheta = 0.25 therefore v = root0.25gl or something
c.) 15/128
Q7
a. show that blah blah
b. 70.5 degrees
c. tan beta = 0.3, beta = 16.7 degrees


all of top of my head so I dont remember the exact figures

Slightly easier than previous papers with a few 'traps'


Yeah I think I got the same as this
Reply 17
Original post by QuangHa
We are nerds, then, according to your argument :-j.

I only need A*, which I think I will definitely be able to get it :biggrin:


That's for sure I would worry more about you if that was M2 because gb will be sky high but M3 nah should be less than 70 for an A*
Reply 18
Original post by dude345
Q1:
lambda = 41.3952
Q2:
a) 1.8 ms/2 towards C
b) 1.3747 ms
c.) time = 0.137s
Q3
a.) -1/80 ms/2
b.) 17.8s
Q4.
a.) show that... no need for an answer
b.) omega = 4.04 rad/s
Q5.
a.) show that force = ... blah blah
b.) 9 marks differential equation where the velocity at height R above the surface was root 5gR/6 (i dont remember that one)
Q6.
a.) show that... blah blah (8 marks)
b.) costheta = 0.25 therefore v = root0.25gl or something
c.) 15/128
Q7
a. show that blah blah
b. 70.5 degrees
c. tan beta = 0.3, beta = 16.7 degrees


all of top of my head so I dont remember the exact figures

Slightly easier than previous papers with a few 'traps'


thanks for posting this! :smile:
found the paper a pretty stressful experience (struggled for ages on Q3ii before realising it was the whole differential equation thing, and I don't really remember ever being given v in terms of x and being asked for acceleration... normally it's the other way around, threw me for a moment!) but my answers all agree with yours, which has got to be good!
was surprised by the pretty straightforward SHM question though
Reply 19
Original post by pavlovscat
thanks for posting this! :smile:
found the paper a pretty stressful experience (struggled for ages on Q3ii before realising it was the whole differential equation thing, and I don't really remember ever being given v in terms of x and being asked for acceleration... normally it's the other way around, threw me for a moment!) but my answers all agree with yours, which has got to be good!
was surprised by the pretty straightforward SHM question though


Shm was fairly simple that's for sure, I can imagine they tried to check whether we actually that a = v dv/dx and using basic principles get the right answer, I can imagine it confused some of the candidates but tbh it was fairly straightforward. There was a number of Show that ... so we might get slightly higher gb than average.

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