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MEI logarithms HELP ME!!!!

I'm a AS Level student doing MEI maths, i have found most parts of the course pretty straight forward but i missed a lot of school when logarithms and exponentials were covered. i just tried to attempt to MEI Chapter assessment and realised that i'm really struggling with understanding anything to do with logarithms other than the really simply stuff. does anyone know any good ways to learn this stuff?? many thanks.

Reply 1

boromir9111

Post a question you're struggling with and then you'll be able to get appropriate responses to your specific weak spot on this topic!

Reply 2

tehforum

See attached.

Enjoy.

there are plenty of online resources... for instance

http://www.themathpage.com/aprecalc/logarithms.htm

Reply 4

lilangeldanni

Original post by the bear

there are plenty of online resources... for instance

http://www.themathpage.com/aprecalc/logarithms.htm

this is actually what i needed, the way MEI explains stuff just goes straight over my head. cheers for this :smile:

Reply 5

lilangeldanni

http://integralmaths.org/resources/file.php/32/MEI/11_Logarithms/c2lass.pdf

thats the link to the specific chapter assessment struggling on 4 part 3 i can work out what 2x is but when do i go from there? havent got any further than this but the last part will probably be even worse.

Reply 6

boromir9111

Original post by lilangeldanni

Do you mind typing out the question? Can't access it from the site.

Reply 7

tehforum

Original post by boromir9111

Do you mind typing out the question? Can't access it from the site.

3^2x=5

Well if you've worked out 2x

log3^2x=log5
2xlog3=log5
2x= log5/log3
x = (log5/log3)/2

Reply 8

lilangeldanni

yeah i thought that was what i was to do but i wasn't sure whether it was asking me to actually work out the answer as 0.732 or whether i was just to leave it as (log5/log3)/2

Reply 9

tehforum

Original post by lilangeldanni

yeah i thought that was what i was to do but i wasn't sure whether it was asking me to actually work out the answer as 0.732 or whether i was just to leave it as (log5/log3)/2

3sf.

so 0.732

Reply 10

itsn0b0dy

Original post by tehforum

See attached.

Enjoy.

this was incredibly useful! thank you so much.

is there any chance you could tell me where you got these from, or if you could provide the links to any more topics?

Reply 11

tehforum

Original post by itsn0b0dy

this was incredibly useful! thank you so much.

is there any chance you could tell me where you got these from, or if you could provide the links to any more topics?