The Student Room Group

ocr f321 f322 questions and answers revision

Scroll to see replies

Reply 20
Original post by Natalie21
What notes are these?



They're actually less volatile due to the hydrogen bonds..

hi can you ask me questions and no they are notthing
Original post by otrivine
hi can you ask me questions and no they are notthing


On what?
Reply 22
Original post by Natalie21
On what?


on chem unit 1 cause the exam is in 2 weeks :s-smilie: so scary how are you ?by the way
Original post by otrivine
on chem unit 1 cause the exam is in 2 weeks :s-smilie: so scary how are you ?by the way


I'm fine thanks :biggrin:

Definition of a mole
Original post by Natalie21
What notes are these?



They're actually less volatile due to the hydrogen bonds..


Yeah...uhm...that was a uhm...trick question :rolleyes: :redface:
Reply 25
Original post by PrincessMedic
Yeah...uhm...that was a uhm...trick question :rolleyes: :redface:


hi shall we ask each other questions :wink:
Original post by otrivine
hi shall we ask each other questions :wink:


Yeah sure :smile: Only unit 1 though, please :biggrin:
Original post by PrincessMedic
Yeah...uhm...that was a uhm...trick question :rolleyes: :redface:


That's what I thought :wink:

Original post by otrivine
hi shall we ask each other questions :wink:


Original post by PrincessMedic
Yeah sure :smile: Only unit 1 though, please :biggrin:


Sure :smile:
Reply 28
Original post by Natalie21
I'm fine thanks :biggrin:

Definition of a mole


amount of substance containing many particles as there are carbon atoms in exactly 12g of a carbon-12 atom
Original post by otrivine
amount of substance containing many particles as there are carbon atoms in exactly 12g of a carbon-12 atom


better wording would be "in exactly 12g of carbon-12 atoms" - otherwise doesn't really make sense :P

correct a.k.a avagadro's constant :smile:
Original post by otrivine
amount of substance containing many particles as there are carbon atoms in exactly 12g of a carbon-12 atom


6.02*10^23 of a molecule, always add the number or avagardo's constant
Reply 31
Original post by Natalie21
better wording would be "in exactly 12g of carbon-12 atoms" - otherwise doesn't really make sense :P

correct a.k.a avagadro's constant :smile:


thanks more :wink:
Reply 32
Original post by Rainingshame
6.02*10^23 of a molecule, always add the number or avagardo's constant

thanks can u ask me now?
Original post by otrivine
thanks more :wink:


your turn...
Reply 34
Original post by Natalie21
your turn...

state one use of NaF
Original post by otrivine
thanks can u ask me now?


Define a mole.
As a bonus define relative atomic mass. 3 Marks
I did unit 1 in Jan (78/90 A :smile:) so here's a unit 2 question:
Write the balanced structural equation for the complete oxidation of propan-1-ol using [O] to represent the oxidising reagent. What is the name of the oxidising reagent and the catalyst used?
Reply 36
Original post by Rainingshame
Define a mole.
As a bonus define relative atomic mass. 3 Marks
I did unit 1 in Jan (78/90 A :smile:) so here's a unit 2 question:
Write the balanced structural equation for the complete oxidation of propan-1-ol using [O] to represent the oxidising reagent. What is the name of the oxidising reagent and the catalyst used?


me too i did the jan paper for chem but got a B 65/90
well done

-is the weighted mean mass of an atom of an element compared with 1/12th of the mass of carbon-12 atom .
- ch3ch2oh + 2(O) to give ch3ch2cooh
Original post by otrivine
me too i did the jan paper for chem but got a B 65/90
well done

-is the weighted mean mass of an atom of an element compared with 1/12th of the mass of carbon-12 atom .
- ch3ch2oh + 2(O) to give ch3ch2cooh


You missed off the +2H2o at the end, that's 2 marks lost. And also you forgot the second part it's acidified potassium dichromate. The catalyst is h2SO4.
got a question on unit 2 for me?
Explain the trends in ionisation energy and atomic radius across a period. (3 marks)
Original post by otrivine
state one use of NaF


No idea - never learnt this.

Quick Reply

Latest

Trending

Trending