The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

solve sec(x) = - 5

Hi,

To solve sec (x) = (-) 5 you would have to look at it as 1/cos (x) = -5 then doing cos (x) = - 0.2 but I'm not sure what you do from here to find all the values between the interval 0<x>2(pi) in radians

Anyone help please?

Thanks
cos (2pi - x) = cos x
Reply 2
Avatar for raheem94
raheem94
13
Original post by Macromolecular
Hi,

To solve sec (x) = (-) 5 you would have to look at it as 1/cos (x) = -5 then doing cos (x) = - 0.2 but I'm not sure what you do from here to find all the values between the interval 0<x>2(pi) in radians

Anyone help please?

Thanks


cosx=−0.2  ⟹  x=cos−1(−0.2)=… cosx = -0.2 \implies x = cos^{-1} (-0.2) = \ldots

Now using the method(i.e. cast/graphs/general solutions) you prefer, find the other solutions in the given range.

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you