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Original post by L'Evil Fish
:facepalm:

I differentiated the second bits randomly xF

My Username is really Poisson Distribution :mmm:


:rofl:

Think it should be π[x33+4x32+9lnx]14\pi \left[ \frac{x^3}{3} + 4x^{\frac{3}{2}} + 9\ln x \right]_1^4
Original post by justinawe
:rofl:

Think it should be π[x33+4x32+9lnx]14\pi \left[ \frac{x^3}{3} + 4x^{\frac{3}{2}} + 9\ln x \right]_1^4


Yeah I have that now! :biggrin: (in the edit)

My Username is really Poisson Distribution :mmm:
Original post by L'Evil Fish
Yeah I have that now! :biggrin: (in the edit)

My Username is really Poisson Distribution :mmm:


Good :biggrin: reading that was a massive pain... I read it wrong at first and got a completely different answer! Learn LaTeX please :tongue:
Original post by justinawe
Good :biggrin: reading that was a massive pain... I read it wrong at first and got a completely different answer! Learn LaTeX please :tongue:


:rofl: sorry :colondollar:
Okay, how do I latex fractions...

Do I have to type in, frac?
And how about Integral sign? And limits? :tongue:

My Username is really Poisson Distribution :mmm:

Spoiler



Oh I give up with latex...

(3x+1) + (1/2)e^2x - *integrate* (1/2)e^2x + 3 dx

Numbers in wrong?

Lol, made that up, did that come up in latex!? :s-smilie:

My Username is really Poisson Distribution :mmm:
(edited 11 years ago)
Reply 7525
All I can see is maths I don't understand. :eek:
What module is all this?
Reply 7526
Original post by Deziah
All I can see is maths I don't understand. :eek:
What module is all this?


Volumes of revolution is C4 if you're with Edexcel (not sure about other exam boards though). :smile:
Original post by usycool1
Volumes of revolution is C4 if you're with Edexcel (not sure about other exam boards though). :smile:


I need Latex tutorials :colonhash: lol, it's C4 with me as well :smile:

My Username is really Poisson Distribution :mmm:
Original post by Deziah
All I can see is maths I don't understand. :eek:
What module is all this?


No idea, I believe it's C4 ( From what Usycool said )....This looks hard...:s-smilie:

Spoiler

(edited 11 years ago)
Original post by Sheel1
No idea, I believe it's C4 ( From what Usycool said )....This looks hard...:s-smilie:


When you learn it, it'll be fine :smile:

Integration (simple start, is opposite of differentiation) so you add one to the power and divide the co efficient by it.

If you differentiate 3x^2 + 4x + 1 you'd get 6x + 4.

If you integrate 6x + 4. You'd get 3x^2 + 4x + c (because c could be any number, we don't know it's 1)

Think of it as anti differentiation, and you can use it to find area under a graph, volume of 3D shapes :smile:

My Username is really Poisson Distribution :mmm:
Original post by Sheel1
No idea, I believe it's C4 ( From what Usycool said )....This looks hard...:s-smilie:

Spoiler



It's a rule :smile:
To find the volume generated by a graph being rotated 360 degrees. You integrate the graph squared and multiply it by Pi

Eg y = x spin it around 360 degrees, what's the.volume between 1 and 2.

square y and you get x^2 right? So integrate that and do things (you'll learn soon) and multiply by pi!

My Username is really Poisson Distribution :mmm:
(edited 11 years ago)
Reply 7531
Original post by Sheel1
No idea, I believe it's C4 ( From what Usycool said )....This looks hard...:s-smilie:

Spoiler



Have you done C2 yet? If not, it'll be hard to explain where the pi comes from. :tongue:

Original post by L'Evil Fish
I need Latex tutorials :colonhash: lol, it's C4 with me as well :smile:

My Username is really Poisson Distribution :mmm:


This is quite useful: http://www.thestudentroom.co.uk/wiki/LaTex :smile:
Original post by L'Evil Fish

Spoiler



Oh I give up with latex...

(3x+1) + (1/2)e^2x - *integrate* (1/2)e^2x + 3 dx

Numbers in wrong?

Lol, made that up, did that come up in latex!? :s-smilie:

My Username is really Poisson Distribution :mmm:


Close :rofl: it's \int, not /int

Just read the article http://www.thestudentroom.co.uk/wiki/LaTex

When I was first learning how to use it, I kept referring to the article on how to do stuff. Now it just comes naturally :biggrin:
Original post by justinawe
Close :rofl: it's \int, not /int

Just read the article http://www.thestudentroom.co.uk/wiki/LaTex

When I was first learning how to use it, I kept referring to the article on how to do stuff. Now it just comes naturally :biggrin:


Just read it :colonhash: :lol: were the answers right? For integration by parts?

(3x+1)(e2x)dx\int(3x+1)(e^{2x})dx
(3x+1)[(e2x)/2][e2x2+3]dx(3x+1)[(e^{2x})/2]-\int[\frac{e^{2x}}{2} + 3] dx

[(3x)(e2x)+e2x2]e2x4+3x[\frac{(3x)(e^{2x}) + e^{2x}}{2}] - \frac{e^{2x}}{4} + 3x

:lol:

:lol: trying my new skillz
My Username is really Poisson Distribution :mmm:
(edited 11 years ago)
Original post by L'Evil Fish
Just read it :colonhash: :lol: were the answers right? For integration by parts?

(3x+1)(e2x)dx\int(3x+1)(e^{2x})dx

My Username is really Poisson Distribution :mmm:


I don't see no answers :colonhash:
Original post by justinawe
I don't see no answers :colonhash:


Oops, check last post on previous page, the bottom one :tongue:

My Username is really Poisson Distribution :mmm:
Original post by L'Evil Fish
Just read it :colonhash: :lol: were the answers right? For integration by parts?

(3x+1)(e2x)dx\int(3x+1)(e^{2x})dx
(3x+1)[(e2x)/2][e2x2+3]dx(3x+1)[(e^{2x})/2]-\int[\frac{e^{2x}}{2} + 3] dx

[(3x)(e2x)+e2x2]e2x4+3x[\frac{(3x)(e^{2x}) + e^{2x}}{2}] - \frac{e^{2x}}{4} + 3x

:lol:

:lol: trying my new skillz
My Username is really Poisson Distribution :mmm:


Is that the same as 14e2x(6x1)+c\frac{1}{4}e^{2x}(6x-1)+c

cause that's what I got :tongue:
Original post by justinawe
Is that the same as 14e2x(6x1)+c\frac{1}{4}e^{2x}(6x-1)+c

cause that's what I got :tongue:


Let me see :colone:
It probably is :tongue: because I got something like that in my head :colonhash:

Latex is hurting me now :tongue:

My Username is really Poisson Distribution :mmm:
(edited 11 years ago)
Original post by L'Evil Fish

(3x+1)[(e2x)/2][e2x2+3]dx(3x+1)[(e^{2x})/2]-\int[\frac{e^{2x}}{2} + 3] dx


The second one should be [e2x2(3)]dx\int[\frac{e^{2x}}{2}(3)] dx

multiply not add :colone:
I feel so stupid for failing the coordinate geometry test now! and I think they will use it for my predicted AS grades >_< It's even more simple than the series assignment I did -4/-5 and said it was -4/5 >_< stupid positive negative mistakes! Just did the whole test again in 10minutes without any help and got 100%! but I guess stuff happens

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