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Mechanics help

a particle of mass 3 kg is attached to one end of each of two strings s1 and s2. A particle of mass 2.5kg is attached to the other end of s1, and a particle of mass 1kg is attatched to the other end of s2. The particles are held in positions shown with the strings taut and s1 passing over a smooth fixed peg. The system is released from rest. Find the acceleration of the particles and the tensions in s1 and s2

sorry but idk how to draw a pic to show you but basically its a pulley with another string under the object on the right.
so you have the 2.5kg weight on the left end of the pulley then the 3kg weight on the right end (attatched by the string, s1) of the pulley with a 1kg weight under the 3kg weight attatched together with a different string, s2.

Thanks
(edited 11 years ago)
Reply 1
Are the springs or strings?
Reply 2
Original post by TenOfThem
Are the springs or strings?


strings
Reply 3
if you have the mechanics book by douglas quadling its pg 118 question 6
Reply 4
Original post by SDavis123
strings


Do you want to correct your OP then, to make it easier for anyone else reading
Reply 5
Using For Working Out Stuff P19.png

This?
Reply 6
Set up an equation in T1 and a for the 2.5 mass

Set up an equation in T1, T2, and a for the 3 mass

Set up an equation in T2 and a for the 1 mass

you have 3 equations in 3 unknowns, solve them simultaneously
Reply 7
Original post by TenOfThem
Using For Working Out Stuff P19.png

This?


yes thanks
Reply 8
Original post by TenOfThem
Set up an equation in T1 and a for the 2.5 mass

Set up an equation in T1, T2, and a for the 3 mass

Set up an equation in T2 and a for the 1 mass

you have 3 equations in 3 unknowns, solve them simultaneously



These are the equations I get in order I think I'm going wrong with the bit to do with the bottom string

1. T-2.5g=2.5a
2. 3g +s -t =3a
3. G-s=a

Where s is the pull from the bottom string and t is the tension from upper string


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Original post by SDavis123
These are the equations I get in order I think I'm going wrong with the bit to do with the bottom string

1. T-2.5g=2.5a
2. 3g +s -t =3a
3. G-s=a

Where s is the pull from the bottom string and t is the tension from upper string


Aside from the fact you used a mix of uppercase/lowercase (best to be consistent), they're fine.
Reply 10
Yh sorry about that autocorrect :/


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Reply 11
I'm having trouble solving them simultaneously :/


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Reply 12
Don't worry got it


This was posted from The Student Room's iPhone/iPad App
Reply 13
:angry: got it wrong :'(
This is what I did


This was posted from The Student Room's iPhone/iPad App
Original post by SDavis123
:angry: got it wrong :'(
This is what I did


This was posted from The Student Room's iPhone/iPad App


4th line of writing should say g-a not g+a
Reply 15
Original post by TenOfThem
4th line of writing should say g-a not g+a



ahhhhh thanks
Reply 16
Qn: A particle of mass 3kg 11attached to the lover end B of aThestring upperis fixed to apointend A of the stangon the ceillinga roof. A horizontal force of 201and anOpward vertical force of2.4.91 act upon the particle makingit to be in equilibrium, with theString makingan agle a with theverticle; Find the value of of andthe tension in the string.Help me please
Original post by Wannarex
Qn: A particle of mass 3kg 11attached to the lover end B of aThestring upperis fixed to apointend A of the stangon the ceillinga roof. A horizontal force of 201and anOpward vertical force of2.4.91 act upon the particle makingit to be in equilibrium, with theString makingan agle a with theverticle; Find the value of of andthe tension in the string.Help me please

Its better to start your own thread and not to bump 8 year old threads.
Also, upload a picture of the question and describe what you've tried. You must realize your posted question is almost unreadable.

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