Ok, so there is a moment at A of
15*5g + 10C + 22D = 0, (1)
and vertically, C + D + 5g = 0 (2)
Since g = -9.8,
(1) -147 + 10C + 22D = 0
(2) C + D - 49 = 0
substituting (2) into (1),
C = 49 - D,
-147 + 10(49 - D) + 22D = 0
343 + 12D = 0, D = 28.6N
That's the right answer! I didn't realise it was that simple! I LOVE YOU TTOBY!!!