Got stuck on a question, please see the link for the diagram *link removed*
q5a
Two loudspeakers are one metre apart, and are connected to the same signal. A listener is two metres away from the left speaker on a line which is perpendicular to the line joining the two speakers (see above diagram). Speed of sound in air 340m/s.
a) When both speakers generate a 1000Hz signal what is the phase difference between them?
Sorry if working is hard to follow having been typed up.
Path difference = √12 + √22 = √5
Wavelength = speed/frequency = 340/1000 = 0.34
Using this equation ∅=2πX/wavelength,
(2xπx√5)/0.34 = 41.32243959
The actual answer is 4.435π Radians - can someone please explain where I went wrong?