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Maths AQA C1 revision - 14th January 2013

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Reply 80

mike256

Original post by Carlile

What did everyone get for C on the integration question?

C = -1

Reply 81

Taran Hare

I thought the exam was easier than others but I know ive done some stupid mistakes which i tend to do in a maths exam. I didnt even know their was an integration question lol

Reply 82

Stournslad

Made this exam my little bitch, if you excuse the crude reference

Reply 83

Ferrari_1996

Original post by Taran Hare

I thought the exam was easier than others but I know ive done some stupid mistakes which i tend to do in a maths exam. I didnt even know their was an integration question lol

I don't remember integrating anything either. I think I missed the question out. I just hope that I get atleast a B. What do you think the grade boundries will be? Does anybody want to guess?

Reply 84

Ozzy4321

Yeah that integration question had the most amount of marks for it too. (5 I think)

I think I did really well on this paper, but I have definitely over revised for it. There were certainly some tricky questions in there like the integration and translation.

Reply 85

GregLAD

Original post by Stournslad

Made this exam my little bitch, if you excuse the crude reference

As did i, with kinky whip and chain...i

Reply 86

Fillly

Was the translation from Y=x^2 onto x^2-6x+11 or the other way around?

Reply 87

GregLAD

Original post by Fillly

Was the translation from Y=x^2 onto x^2-6x+11 or the other way around?

I concur

Reply 88

the_googly

I think an answer of:

The graph has been translated by the vector [3....2] would be sufficient enough for three marks going by the past mark schemes.

Reply 89

Ferrari_1996

Original post by Fillly

Was the translation from Y=x^2 onto x^2-6x+11 or the other way around?

The other way around. What was the answer? I said 6 to the right and 11 down.

EDIT: I'm 99% sure that's wrong. I didn't know what to do. Could somebody tell me what to do? My logic was the -6x was not in Y=x^2 so it must've went 6 to the right and +11 wasn't there idea so I thought that turned into a 0 in Y=x^2 by going 11 down.

(edited 11 years ago)

Reply 90

the_googly

Original post by Ferrari_1996

The other way around. What was the answer? I said 6 to the right and 11 down.

I'm sure the answer is 3 to the right and 2 up. After you have completed the square, the vertex is (3,2). The vertx of the y=x^2 is (0,0) therefore the graph has been translated by the vector [3,2]

Reply 91

Ozzy4321

It was y = x^2 - 6x + 11 onto the graph of y = x^2.

You had to use the completed square version of y = (x - 3)^2 + 2.

So the translation was:
[-3]
[-2]

I'm pretty sure about this.

Reply 92

the_googly

What did people get the answer of the length PQ? The question was something to do with Tangents... I used the pythagoras theorem and got underoot 9 as the answer, which = 3.

Reply 93

ZoeLouise15

Original post by the_googly

I'm sure the answer is 3 to the right and 2 up. After you have completed the square, the vertex is (3,2). The vertx of the y=x^2 is (0,0) therefore the graph has been translated by the vector [3,2]

That's what I put in my exam. I did the vector and then stated 3 to the right and 2 up, just in case. :smile:

Reply 94

ThomSDK

Original post by Ferrari_1996

I don't remember integrating anything either. I think I missed the question out. I just hope that I get atleast a B. What do you think the grade boundries will be? Does anybody want to guess?

From what ive heard it was an easy paper in general and i dont believe i dropped any marks. They cannot however make the A boundary above 67/75 due to the gap they must leave for students getting above 90% aiming for A* in maths and the grade boundaries are normally 6 or 7 marks away from eachother so im assuming

62-64 for an A
55-57 for a B
47-49 for a C
Etc

Reply 95

the_googly

Original post by Ozzy4321

It was y = x^2 - 6x + 11 onto the graph of y = x^2.

You had to use the completed square version of y = (x - 3)^2 + 2.

So the translation was:
[-3]
[-2]

I'm pretty sure about this.

Should it be positive 3 and positive 2?

Reply 96

ZoeLouise15

Original post by the_googly

What did people get the answer of the length PQ? The question was something to do with Tangents... I used the pythagoras theorem and got underoot 9 as the answer, which = 3.

I got that one too! What did people do for 6b? Was it integration as I didn't know what to do. :s-smilie:

Reply 97

the_googly

Original post by ZoeLouise15

That's what I put in my exam. I did the vector and then stated 3 to the right and 2 up, just in case. :smile:

Yay!

Reply 98

Ferrari_1996

Original post by the_googly

I'm sure the answer is 3 to the right and 2 up. After you have completed the square, the vertex is (3,2). The vertx of the y=x^2 is (0,0) therefore the graph has been translated by the vector [3,2]