Difference between two statements?

With reference to question 1 c)

What's the difference between the probability of winning one and the probability of winning exactly one?

Thanks.

If you win 2 then you have won 1

If you win exactly 1, you cannot have won 2

The mark scheme has the answer as 3 x P(WLL).

It's making the assumption they win the first prize and not the second or third prize i.e. (LWL) or (LLW).

I don't understand why that's correct.

What do you think the "3x" is doing?

I should probably be more clear. Say the total people is out of 16. Winning = 5/16

The mark scheme has 3 x (5/16)(11/15)(10/14) => (WLL)

But winning once could also involve (11/16)(5/15)(10/14) or (11/16)(10/15)(5/14) => (LWL) and (LLW)

You can either win the first prize, the second prize or the third prize; it doesn't specifically state chances of winning the first prize.

P(WLL) = 5/16 * 11/15 * 10/14

What do you think the 3x is doing

I'm aware of what the 3x is doing; 3x the probability of winning the FIRST prize as there are three people.

3 people?

Where?

P(WLL) = P(LWL) = P(LLW)

So you only need to find one of these and then x3

Unless I have mis-read your question ... possible since I have no idea where you are getting 3 people from

I have no idea where I'm getting 3 people from either lol I meant 3 possible outcomes.

And it appears my working out gives the same answer but in a longer way since P(WLL) = P(LWL) = P(LLW) -_- No idea what my problem was now Must have put the values in wrong the first time. Sorry for wasting your time lol.

And thanks.