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Help with radian question!

Here is the question, I'm puzzled as for part A I got -4.92, but you cant get a negative angle!

Please help

08d6f88cb5292282f53663f0b8bff528.png
Link to question: http://gyazo.com/08d6f88cb5292282f53663f0b8bff528
Think you need to show that piece of working!
Reply 2
Avatar for User32432432
User32432432
OP
3
Original post by Mr M
Think you need to show that piece of working!

I'm using 1/2r^2Q (Q= theta)

0.5(9.2^2)Q=37.4
Q= 37.4 - 42.32
Q= -4.92
Original post by User32432432
I'm using 1/2r^2Q (Q= theta)

0.5(9.2^2)Q=37.4
Q= 37.4 - 42.32
Q= -4.92


Oh dear.

Your first line is correct.

ax=bax=b

does not lead to

x=b−ax=b-a
Reply 4
Avatar for User32432432
User32432432
OP
3
Original post by Mr M
Oh dear.

Your first line is correct.

ax=bax=b

does not lead to

x=b−ax=b-a

Oh my dear lord, Just realised what I missed, feel stupid lol.
Thanks
Did you get 0.89 Rad ?
Reply 5
Avatar for Hasufel
Hasufel
16
try solving the equation first for θ\theta

to get: θ=2Ar2\theta=\frac{2A}{r^2}

then plug the values in
Reply 6
Avatar for Hasufel
Hasufel
16
Original post by User32432432
Oh my dear lord, Just realised what I missed, feel stupid lol.
Thanks
Did you get 0.89 Rad ?


0.8837429 (although difference is tenths of an angle [in degrees])
(edited 11 years ago)
Reply 7
Avatar for User32432432
User32432432
OP
3
Original post by Hasufel
0.8837429

Yea, good I rounded it up 2 sig fig

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