\[\log_3 \frac{4x + 7}{x} = 2 \Leftrightarrow 3^2 = \frac{4x + 7}{x}\]
\[\log_3 \frac{3(4x + 7)}{x} = 2 \Leftrightarrow 3^2 = \frac{3(4x + 7)}{x}\]
\[\log_3 \frac{3(4x + 7)}{x} = 2 \Leftrightarrow 3^2 = \frac{3(4x + 7)}{x}\]
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Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
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