The points A(1,3), B(1,7), C(7,7) lie on the circle (x−4)2+(y−5)2=13 a) draw a sketch b) by considering the gradients on AB and BC show that AC is a diameter of the circle
and for part (b) Gradient of AB = 04 (infinity?) Gradient of BC = 0 not sure how this will help me to show that AC is the diameter? I can see of the sketch that AC is the diameter but how do I use the gradients to show this?
The points A(1,3), B(1,7), C(7,7) lie on the circle (x−4)2+(y−5)2=13 a) draw a sketch b) by considering the gradients on AB and BC show that AC is a diameter of the circle
and for part (b) Gradient of AB = 04 (infinity?) Gradient of BC = 0 not sure how this will help me to show that AC is the diameter? I can see of the sketch that AC is the diameter but how do I use the gradients to show this?
Thanks!
Not sure if that question is right. But try considering the gradients OA and OC instead, where O is the origin of the circle
The diameter? I said that above but I thought it wanted working out using the gradients of AB and AC
One of the circle theorems states that the angle formed by a triangle in a circle when the hypotenuse is the diameter is a right angle. show that the two lines are perpendicular and that the hypotenuse passes through the centre of the circle.