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Implicit equations help

I'm stuck on question 4


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Oh that's horrible!

Really!

You have separated the variables correctly but the next line is just drivel. Try substituting a couple of numbers and you will agree.

Integrate the y term by recognising a logarithmic integral and the x term by making a substitution for the denominator or by expressing it in divided out form.
Reply 3
Original post by SDavis123
And this is as far as I've got


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Line 1 = good

Line 2 = rubbish

xx11x\dfrac{x}{x-1} \not= 1-x

Ditto the y side being incorrect
Reply 4
Original post by Mr M
Oh that's horrible!

Really!

You have separated the variables correctly but the next line is just drivel. Try substituting a couple of numbers and you will agree.

Integrate the y term by recognising a logarithmic integral and the x term by making a substitution for the denominator or by expressing it in divided out form.


Ah yes I see what you mean so take the 2 out of the y bit to make the top differential of the bottom so you'll get ln(y^2 +1) ?


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To explain your misconception:

ab+cab+ac\displaystyle \frac{a}{b+c} \neq \frac{a}{b} + \frac{a}{c}
Original post by SDavis123
Ah yes I see what you mean so take the 2 out of the y bit to make the top differential of the bottom so you'll get ln(y^2 +1) ?


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Sort of.

You need to deal with the 2 you just threw away.
Reply 7
Ah yh sorry, (1/2)(ln(y^2 + 1))


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Original post by SDavis123
Ah yh sorry, (1/2)(ln(y^2 + 1))


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Yes.
Reply 9
Original post by Mr M
Yes.



I'm not sure on the x part but I said

x/(x-1)=x(x-1)^-1

And when I integrate that I get

((-x^2)/4).(x-1) that right?


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Original post by SDavis123
I'm not sure on the x part but I said

x/(x-1)=x(x-1)^-1

And when I integrate that I get

((-x^2)/4).(x-1) that right?


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You seem to be making up your own integration rules now.

xx1=x1+1x1=1+1x1\displaystyle \frac{x}{x-1}=\frac{x-1+1}{x-1}=1+\frac{1}{x-1} which I hope you can integrate.
Reply 11
Original post by Mr M
You seem to be making up your own integration rules now.

xx1=x1+1x1=1+1x1\displaystyle \frac{x}{x-1}=\frac{x-1+1}{x-1}=1+\frac{1}{x-1} which I hope you can integrate.


Ermmm ok haha but how did you get

x/(x-1)=(x-1+1)/(x-1) ?


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Original post by SDavis123
Ermmm ok haha but how did you get

x/(x-1)=(x-1+1)/(x-1) ?


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Because x=x1+1x = x - 1 + 1
Reply 13
Original post by SDavis123
Ermmm ok haha but how did you get

x/(x-1)=(x-1+1)/(x-1) ?


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Because x-1+1 = x ???

Edit: SNAP!
Original post by davros
Because x-1+1 = x ???


Snap!

Now your edit made my snap look stupid!
(edited 11 years ago)
Reply 15
Original post by Mr M
Because x=x1+1x = x - 1 + 1


Ah yh obviously can't believe I didn't see that haha


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Reply 16
Original post by Mr M
Snap!

Now your edit made my snap look stupid!


I'm trying to write maths while watching the football. I should stop now before I write something stupid!
Reply 17
Original post by davros
I'm trying to write maths while watching the football. I should stop now before I write something stupid!


Football? And there was me thinking mathematicians were clever :tongue:

And what's the next move after



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Original post by SDavis123
Football? And there was me thinking mathematicians were clever :tongue:

And what's the next move after



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Integrate it - come on this is getting a bit painful!
Reply 19
Original post by Mr M
Integrate it - come on this is getting a bit painful!


Yh I did, did you see the picture?


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