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Stats help

http://www.ocr.org.uk/Images/65851-question-paper-unit-4732-probability-statistics-1.pdf

The very last bit of question 8 why is it not just (5/6)^9 (1/6)?
(edited 11 years ago)
Reply 1
Bump.
Reply 2
Bump.
Let me open the file now. Hmmm, would it not be:

(5/6)^9 * (1/6)

Oh that is what you put, what's the answer?
(edited 11 years ago)
Reply 4
(5/6)^9 * (1/6) + (5/6)^10 * (1/6) + (5/6)^11 * (1/6) + (5/6)^12 * (1/6)
Reply 5
Original post by L'Evil Fish
Let me open the file now. Hmmm, would it not be:

(5/6)^9 * (1/6)

Oh that is what you put, what's the answer?


(5/6)^9 * (1/6) + (5/6)^10 * (1/6) + (5/6)^11 * (1/6) + (5/6)^12 * (1/6)
Original post by Music99
(5/6)^9 * (1/6) + (5/6)^10 * (1/6) + (5/6)^11 * (1/6) + (5/6)^12 * (1/6)


Oh right, we've assumed that when he throws it, it's a six.

However, on his third throw,.it can still not be a six. So you have to carry on. Up until (5/6)^12 * (1/6) because if the six hasn't been thrown by then, he'll have thrown ir 4 times.

Make sense?
Reply 7
Original post by L'Evil Fish
Oh right, we've assumed that when he throws it, it's a six.

However, on his third throw,.it can still not be a six. So you have to carry on. Up until (5/6)^12 * (1/6) because if the six hasn't been thrown by then, he'll have thrown ir 4 times.

Make sense?


Ohhhhh right! makes sense yeah, it's all in the wording! And this is why I don't like stats. Thank you.
Original post by Music99
Ohhhhh right! makes sense yeah, it's all in the wording! And this is why I don't like stats. Thank you.


No problem, if I was thrown thrice by him and it was a six. Then it'd be what we initially said.
Reply 9
Original post by L'Evil Fish
No problem, if I was thrown thrice by him and it was a six. Then it'd be what we initially said.


Yeah that makes sense.
Original post by Music99
Yeah that makes sense.


:smile:

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