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c2 circles

a) show that the line y=3x + 10 is a tangent to the circle x^2 + y^2 = 10

b) draw a sketch showing the line and the circle above and hence write down the equation of another line 'passing through the point (0,10)' which is also a tangent to the circle x^2 + y^2 =10


thank you so much for any help :smile:

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Reply 1
cheers :biggrin:
Original post by lolman42
a) show that the line y=3x + 10 is a tangent to the circle x^2 + y^2 = 10

b) draw a sketch showing the line and the circle above and hence write down the equation of another line 'passing through the point (0,10)' which is also a tangent to the circle x^2 + y^2 =10


thank you so much for any help :smile:


Well, substitute the equation of the line into the circle and consider the nature of the resulting quadratic.

Hint:

It's a tangent if

b2=4acb^2 = 4ac
Reply 3
Original post by Indeterminate
Well, substitute the equation of the line into the circle and consider the nature of the resulting quadratic.

Hint:

It's a tangent if

b2=4acb^2 = 4ac


sorry I got part a) but for b)? :smile: thanks :smile:
Original post by lolman42
sorry I got part a) but for b)? :smile: thanks :smile:


Hint:

The line can be horizontal, you know :smile:
Reply 5
Original post by Indeterminate
Hint:

The line can be horizontal, you know :smile:


hmmm... still not to sure .. :colondollar:
Reply 6
Original post by Indeterminate
Hint:

The line can be horizontal, you know :smile:


Not sure that helps
Reply 7
Original post by TenOfThem
Not sure that helps


do you mind explaining it, tenofthem? thanks .
Reply 8
Original post by lolman42
hmmm... still not to sure .. :colondollar:


Use symmetry

I assume that you have found where the first line met the circle ... symmetry will tell you where this new line meets the circle

Then you have 2 points, therefore an equation
Original post by lolman42
hmmm... still not to sure .. :colondollar:


(0, root 10) is at the top of the circle, right?

So, which flat line touches the circle at this point?

Think!!! :tongue:

If you can't get it, get back to me :smile:
(edited 11 years ago)
Original post by lolman42
do you mind explaining it, tenofthem? thanks .


Takes time to type you know !
Original post by Indeterminate
(0,10) is at the top of the circle, right?


No, it isn't
Reply 12
Original post by TenOfThem
Use symmetry

I assume that you have found where the first line met the circle ... symmetry will tell you where this new line meets the circle

Then you have 2 points, therefore an equation


nope I haven't found where the first line meets the circle :s-smilie:
Original post by lolman42
nope I haven't found where the first line meets the circle :s-smilie:


well it is not much beyond the work you did for (a)
Original post by TenOfThem
No, it isn't


eek

(0,10)(0,\sqrt{10})
Reply 15
Original post by TenOfThem
well it is not much beyond the work you did for (a)


sub in when x =0 to find y?
Original post by lolman42
sub in when x =0 to find y?


no

didn't you have a quadratic with a single solution as part of (a)
Reply 17
Original post by TenOfThem
no

didn't you have a quadratic with a single solution as part of (a)


yeap..:colondollar:
Reply 18
Original post by TenOfThem
no

didn't you have a quadratic with a single solution as part of (a)


subbing the equation of the line into the circle I get

7x^2 + 60x + 90 = 0

what do I do from here?:smile:
Original post by lolman42
sub in when x =0 to find y?


Surely, as it's saying "write down", it's asking for

y=10y=\sqrt{10}

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