Has anyone besides the OP actually tried solving it? I'm reaching a quadratic with no real solutions ...
Nope I haven't but following the basic rules, I would get a quadratic and then factorise that (if its possible) if not, maybe the quadratic formula? if not, then I dont know :P
Yes you're right it's fine, I misread 5sin(x) as sin(x).
To the OP: yes it is just cos2(x)=1-sin2(x), substitute in and solve
I subbed it back, got: 6sin^2 theta - 5sin theta - 1 = 0 Turned it into: 6x^2 -5x -1 Factorised: (X-1)(6x+1) Does that make sinx = -1/6 , 1 And then do I put that back into the 7 - 6cos^2 theta = 5sin theta ?
I subbed it back, got: 6sin^2 theta - 5sin theta - 1 = 0 Turned it into: 6x^2 -5x -1 Factorised: (X-1)(6x+1) Does that make sinx = -1/6 , 1 And then do I put that back into the 7 - 6cos^2 theta = 5sin theta ?
I subbed it back, got: 6sin^2 theta - 5sin theta - 1 = 0 Turned it into: 6x^2 -5x -1 Factorised: (X-1)(6x+1) Does that make sinx = -1/6 , 1 And then do I put that back into the 7 - 6cos^2 theta = 5sin theta ?